two casks contain mixture of liquids a and b .in the first cask a:b::7:3and the second caska:b::3:1.in what ratio must the mixture from the two Cask be taken to give a mixture in which a:b::11:4?
That's a complex question as you can notice the first mixture has ratio of 7:3 which makes 10 parts. Similarly, mixture b has 4 parts and the resultant mixture needs to have 15 parts. Taking the LCM of these three, we get 60, and comparing these ratios out of 60 parts, you will notice that the derived ratios will be
A- 42:18
B- 45:15
Now we all can notice that the parts of liquid a are higher in the mixture B and the parts of liquid b are higher in mixture A. This creates an ambiguity for the mixing process and to achieve the desired ratio.
But if we follow the weighted average method of cross multiplication only on one of the ratios, say for liquid a, we get
7/10 : 3/4
11/15
3/4 - 11/15 : 11/15 - 7/10
This gives the ratios of mixture A and B as 1:2
