two vessels contain water and alcohol in the ratios 1:2 and 3:4 the two solution are then mixed by taking 6 liters from the first vessel and 35 liter from the second . find the ratio of alcohol to water in resultant ratio
Hello,
The given numerical is quite easy but tricky example of ratio and proportion.
Consider first vessel,
The ratio of water to alcohol is 1 : 2
Now, 6 L solution is taken from first vessel.
Let, quantity of water be x. So, quantity of alcohol will be 2x.
So, x + 2x = 6
So, x = 2 L and 2x = 4L
Hence, 2 Liters of water and 4 liters of alcohol is taken out from first vessel.
Similarly, now consider 2nd vessel.
The ratio of water to alcohol is 3:4
35 Liters of solution is taken out.
Let, quantity of water taken out = 3x
So, quantity of alcohol taken out = 4x
Now, 3x + 4x = 35
So, x= 5
Hence, quantity of water taken out = 3x = 15 Liters
and quantity of Alcohol taken out = 4x = 20 Liters
Now, Solution is made by mixing 6L of solution from first vessel and 35L of solution from second vessel.
So, Total quantity of water in resultant solution = 15 L + 2 L = 17 L
and Total quantity of alcohol in resultant solution = 20L + 4L = 24 L
Hence, Ratio of Alcohol to Water in resultant solution = 24 : 17
Best Wishes.