A Compound on analysis gave the following percentage Composition C=54. 55% H = 9.09%, o=36.36%. Determine the empirical formula of the Compound.
Answers (2)
11th Jun, 2025
To find the empirical formula for the composition you have asked is :
- C = 54.55% ÷ 12 = 4.55
- H = 9.09% ÷ 1 = 9.09
- O = 36.36% ÷ 16 = 2.27
Now, divide all these with the smallest value obtained in the calculation (2.27):
C = 2, H = 4, O = 1
The Empirical formula of the compound is: C2H4O
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11th Jun, 2025
To find the empirical formula he composition you have mentioned is :
1. C = 54.55% / 12 = 4.55
2. H = 9.09% / 1 = 9.09
3. O = 36.36% / 16 = 2.27
Now, divide all these with the smallest value obtained in the calculation (2.27) :
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