a man fires a bullet of mass 200g at a speed of 5m/s the gun is of one of mass.by what velocity the gun rebounds backwards
Answer (1)
Student Expert
15th Nov, 2019
Dear student, mass of bullet, m1= 200 g = 0.2 kg
mass of gun, m2= 1 kg
velocity of bullet, V1= 5 m/s
velocity of GUN, V2= ?
According to law of conservation of linear momentum,
Linear momentum=Linear momentum
before firing after firing
=>. 0 = m1 V1 + m2 V2
=>. V2 = - m1 V1/m2
=>. - 0.2×5×1
=>. V2 = - 1 m/s
Therefore, velocity of the gun = -1 m/s.
All the best
Hope this helps
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