Question : ABCD is a cyclic quadrilateral and BC is the diameter of the related circle on which A and D also lie. $\angle \mathrm{BCA}=19°$ and $\angle \mathrm{CAD}=32°$. What is the measure of $\angle \mathrm{ACD}$?
Option 1: 41°
Option 2: 38°
Option 3: 40°
Option 4: 39°
Correct Answer: 39°
Solution :
Given,
$\angle{CAD}=32°$ and $\angle{BCA}=19°$
We know, that the angle formed by the diameter is 90°.
⇒ $\angle{BAC}=90°$
The sum of the opposite angle of a quadrilateral = 180°.
⇒ $\angle{CAD}+\angle{BAC}+\angle{BCA}+\angle{ACD}=180°$
⇒ $32°+90°+19°+\angle{ACD}=180°$
⇒ $141°+\angle{ACD}=180°$
⇒ $\angle{ACD}=180°-141°$
⇒ $\angle{ACD}=39°$
Hence, the correct answer is 39°.
Related Questions
Know More about
Staff Selection Commission Combined Grad ...
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Get Updates Brochure
Your Staff Selection Commission Combined Graduate Level Exam brochure has been successfully mailed to your registered email id “”.
Upcoming Exams
Trending Articles around SSC CGL
