Question : An airplane goes 14 km due east and then 48 km due north. How far is it from its initial position?
Option 1: 14 km
Option 2: 48 km
Option 3: 50 km
Option 4: 28 km
Correct Answer: 50 km
Solution :
By Pythagoras theorem,
$(AC)^2 = (AB)^2+(BC)^2$
⇒ $(AC)^2=(14)^2 + (48)^2$
⇒ $(AC)^2 = 196+ 2304$
⇒ $AC = \sqrt{2500}$
⇒ $AC = 50\ \mathrm{km}$
Hence, the correct answer is 50 km.
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