an electric heater rated as 2kw is used to heat 200 kg of water from 10c to 70c . the time taken is
Answer (1)
Student Expert
16th Mar, 2020
Hello Chanchal,
Hope you are doing well.
Given, P = 2 kW = 2000 W
Mass of water = 20 kg = 20,000 g
Rise in temperature, dθ = θ2 - θ1 = 30 - 10 = 200C
We know that specific heat of water, (c)= 1 cal g-1 0C-1
Heat produced by heater in time t = P X t = 2000 X t joule = 2000 t4.2 calories (since, 1 cal = 4.2 Joules)
Heat taken by water = mc (θ2 - θ1 ) = 20,000 X 1 X 20= 4,00,000 calories
As, heat produced by heater = Heat taken by water
Hence, 2000 t4.2 = 4000000n solving,
we get :t = 840 sec
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