Arrange the following compounds in the correct order of dipole moment.
H 2 O > NH 3 > NF 3 > BeF 2 = CH 4
i.e., the dipole moment of the compounds is H 2 O = 1084D, NH 3 = 1.49D,
NF 3 =0.24D, BeF 2 = CH 4 = 0
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H 2 O > NH 3 > NF 3 > BeF 2 = CH 4
i.e., the dipole moment of the compounds is H 2 O = 1084D, NH 3 = 1.49D,
NF 3 =0.24D, BeF 2 = CH 4 = 0
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