Cr2o72- +Fe+2 ===Fe+3+Cr+3 by ion electron method
Answer (1)
Student Expert
23rd Dec, 2020
Hey!
this is a redox reaction, where dichromate is the oxidizing agent .
and here we would use half equation method:
So, reduction half equation is :
Cr2O72- + 14 H+ + 6e- => 2Cr3+ + 7H2O (l)
and the oxidation half equation is :
Fe2+ => Fe 3+ + e-
and then add these both equations in such a way that all the electrons are eliminated:
6Fe2+ + Cr2O72- + 14H+ => 6Fe3+ + 2Cr3+ + 7H2O (l)
hope it helps, thanks!
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