Question : Find the perimeter of a major sector of a circle of radius 12 metres, whose minor sector subtends an angle of 75° at the centre.
Option 1: $(24 + 5π)$ metres
Option 2: $(24 + 19π)$ metres
Option 3: $(24 – 5π)$ metres
Option 4: $(24 – 19π)$ metres
Correct Answer: $(24 + 19π)$ metres
Solution :
Here, we have a radius of the circle = 12 m and a minor sector angle subtends an angle = 75º
Angle subtended by major arc = 360º – 75º = 285º
Perimeter of major arc = $2 \times \pi \times r \times \frac{\theta}{360º} + 2r$
$= 2 \times \pi \times 12 \times \frac{285º}{360º} + 2 \times 12$
$= (19\pi + 24$) metres
Hence, the correct answer is ($24 + 19\pi$) meters.
Related Questions
Know More about
Staff Selection Commission Sub Inspector ...
Application | Eligibility | Selection Process | Result | Cutoff | Admit Card | Preparation Tips
Get Updates Brochure
Your Staff Selection Commission Sub Inspector Exam brochure has been successfully mailed to your registered email id “”.
Upcoming Exams
Trending Articles around SSC CPO
