heat produced by combustion of 1gm of C6H6 at constant volume is 41. 80kj at 298 calculate value of enthalpy of cumbustion of benzene at 298
Answer (1)
31st Mar, 2020
hi,
Reaction of combustion in benzene.
C6H6 + 7½O2 (g) -----> 6CO2 (g) + 3H2O (l)
In the above reaction O2 and CO2 are the only gases.
g = no. of moles of products – no. of moles of reactants
= 6 - 7½ = - 1 ½ = -3/2
Given values U = 3263.9 kJ/mol; T = 298 K;
As we know,
H =U +ng RT R = 8.314
As this is an exothermic reaction,H is negative.
H = (- 3263.9 kJ/mol) + (-3/2) (298 K)
= (- 3263.9 kJ/mol) + (-3/2) (2.477)
= (- 3263.9 kJ/mol) – 3.716 kJ/mol
H = - 3267.6 kJ/mol
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