if A=[cosa -sina sina cosa] then A^32=[0 -1 0 0] then a=
Answer (1)
12th Jul, 2020
This should be 2*2 matrix, otherwise it would not make any sense.
So, multiplying A by A, we get A^2 = [Cos2a -Sin2a Sin2a Cos2a]. Doing the same 32 times, you will get A^32 = [Cos32a -Sin32a Sin32a Cos32a]
Comparing the given data with this, we get cos32a = 0 and sin32a = 0 and -sin32a = -1 which seems to be invalid as it is saying that sin32a = 0 = 1 which is not possible. So, no such a exists.
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