if angel A angel B angel C =180 then show that sin(B+C)sinA
A+B+C=180
B+C=180-A
sin(B+C)=sin(180-A)=sinA (As,sin(180- θ)=sin θ)
So,sin(B+C) = sinA
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A+B+C=180
B+C=180-A
sin(B+C)=sin(180-A)=sinA (As,sin(180- θ)=sin θ)
So,sin(B+C) = sinA
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