Question : If the angle of elevation of a cloud from a point 200 m above a lake is $30^\circ$ and the angle of depression of its reflection in the lake is $60^\circ$. Then the height of the cloud above the lake is:
Option 1: 100 m
Option 2: 200 m
Option 3: 300 m
Option 4: 400 m
Correct Answer: 400 m
Solution :
Given: The angle of elevation of a cloud from a point 200 m above a lake is $30^\circ$ and the angle of depression of its reflection in the lake is $60^\circ$.
Let the dotted line represent the lake, point C be the position of the cloud, point A is a point 200 m above the lake and C' is the reflection of the cloud in the lake.
Also, let BC = $x$ m and AB = $y$ m.
So, the height of the cloud above the lake is ($x$+200) m.
In $\triangle$ABC,
$\tan30°=\frac{x}{y}$
⇒ $y=x\sqrt3$ --------------------(equation 1)
In $\triangle$ABC',
$\tan60°=\frac{x+200+200}{y}$
⇒ $y\sqrt3=x+400$
⇒ $(x\sqrt3)\sqrt3=x+400$ (putting the value of $y$ from equation 1)
⇒ $3x–x=400$
⇒ $x=\frac{400}{2}$
⇒ $x$ = 200 m.
Hence, the correct answer is (200 + 200) = 400 m.
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