if the distance of Earth and Sun increases by 125% of its present value then the duration of one year will be
Hello,
So let us suppose,
r1= initial radius
r2=final radius
r2=r1+125%r1=9/4r1
t1=initial duration of 1 year
t2=final duration of 1 year
by Kepler's law we know that t^2 is directly proportional to r^3
therefore
(t2/t1)^2=(r2/r1)^3
t2/t1=(r2/r1)^(3/2)
t2=t1*(9/4r1/r1)^(3/2)
t2=t1*(3/2)^3
t2=365*27/8
this will be the duration of 1 year if the distance of earth and sun increases by 125%.
I hope this helps.
All the best!