Question : In triangle STU, V is a point on the side ST and W is a point on the side SU such that VWUT is a trapezium. Given that VW : TU = 2 : 7, what is the ratio of the area of trapezium VWUT to the area of the triangle STU?
Option 1: 4 : 49
Option 2: 4 : 45
Option 3: 45 : 49
Option 4: 49 : 81
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Correct Answer: 45 : 49
Solution :
Given, $VWUT$ is a trapezium and $VW \parallel UT$
In $\triangle STU$, $VW \parallel UT$
So, $\triangle SVW \sim \triangle STU$
We know, that the ratio of the area of similar triangles is equal to the ratio of the squares of corresponding sides of similar triangles.
So, $Area(\triangle SVW) : Area(\triangle STU) = VW^2 : TU^2$
⇒ $Area(\triangle SVW) : Area(\triangle STU) = 4 : 49$
Now, $\frac{Area (VWUT)}{Area(\triangle STU)} = \frac{(Area(\triangle STU) – Area(\triangle SVW))}{Area(\triangle STU)}$
⇒ $\frac{Area (VWUT)}{Area(\triangle STU)} =1- \frac{ Area(\triangle SVW)}{Area(\triangle STU)}$
⇒ $\frac{Area (VWUT)}{Area(\triangle STU)} =1- \frac{4}{49}$
⇒ $\frac{Area (VWUT)}{Area(\triangle STU)} =\frac{45}{49}$
Hence, the correct answer is 45 : 49.
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