n2 + 3 H2 receiver with 2 NH3 at 298 Kelvin given KP equals to 6.8 into 10 power 5
Answer (1)
29th May, 2020
Hello!!!!
Hope you are doing great!!!
If you want to find Kc, then the procedure is as follows:::;
As per the question reaction is as follows:
N2+3H2 gives rise to 2NH3
Kp=Kc*(RT)^Δ n
Δn= -2 (As per the given reaction)
Given Kp=6.8*10^5
R=8.314 atm.lit/mol.k
T=298 Kelvin
6.8*10^5 = Kc/(RT)^2
Kc=(6.8*10^5) x (RT)^ 2
Kc=(6.8*10^5) x (8.318 * 298 )^2
On Solving,We get Kc=4.5*10^12
Hope it helps!!!!
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