one litre of an unknown gas weighs 1.25 gm at N.T.P.
Dear aspirant,
I assume you are looking for the following solution:
Volume at STP of one more is 22.4 l, and the volume at NTP of one mole is 24 l.
As per the Charles law, the formula is V1 / T1 = V2 / T2.
When 24 l has 1 mole then 1 l will have 1 / 24 moles which is equal to 0.04 moles.
And the molar mass of oxygen comes to 32 g.
Hope this helps. Thank you.
Hello there!
Greetings!
Although you haven't completed your question but I got it and providing its solution below :-
We know that the Volume at STP of one mole is 22.4 l, and the volume at NTP of one mole is 24 l.
As per the Charles law, the formula is V1 / T1 = V2 / T2.
When 24 l has 1 mole then 1 l will have 1 / 24 moles which is equal to 0.04 moles.
And the molar mass of oxygen comes to 32 g.
Thankyou
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