Question : Reema runs $\frac{5}{4}$ times as fast as Rekha. In view of this Reema allows Rekha a lead of 50 metres to Rekha in a friendly race competition. What is the distance from the starting point where both Reema and Rekha meet?
Option 1: 250 m
Option 2: 225 m
Option 3: 200 m
Option 4: 240 m
Correct Answer: 250 m
Solution :
Reema runs $\frac{5}{4}$ times as fast as Rekha
Rekha gives a lead of 50 m to Reema
Let's assume
Reema runs 5 metres for every 4 metres Rekha runs.
Rekha has a lead of 1 m than Reema.
According to the question, Rekha gives a lead of 50 m to Reema
Then Reema will have this lead by covering 50 × 5 = 250 m
They will meet at a point 250 m from the starting point.
Hence, the correct answer is 250 m.
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