sinA+sinB how many value of this
Answers (2)
23rd Jul, 2020
Dear aspirant,
The answer to your question is as follows:
Sin A +Sin B=2[{sin(A+B}/2}{cos(A-B)/2}]
proof:
sin(X+Y)+sin(X-Y)=2(sinXcosY)
let X+Y=A
X-Y=B
X=(A+B)/2 & Y=(A-B)/2
by substituting we get:
sin A +sin B=2[{sin(A+B)/2}{cos{A-B)/2}]
Hope this was useful.
Comments (0)
23rd Jul, 2020
There is only one value given by the formula below:
Answer goes like
sinA+ sinB =2[{sin(A+B)/2} { cos(A-B) /2}]
proof is given as follows:
sin(X+Y) + sin(X-Y) = 2(sinXcosY)
let X + Y = A and X - Y = B
X = (A + B)/2 & Y = (A - B)/2
By Substituting, we obtain the following equation
sinA+ sinB =2[{sin(A+B)/2} { cos(A-B) /2}]
Hence the above equation gives the value of your question
Hope you undersood.
Thank You!!
Comments (0)
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