Question : The outer circumference of the circular race track is 528 metres. The track is everywhere 14 metres wide. The cost of levelling the track at the rate of Rs. 10 per sq. metre is:
Option 1: Rs. 77,660
Option 2: Rs. 66,760
Option 3: Rs. 76,760
Option 4: Rs. 67,760
Correct Answer: Rs. 67,760
Solution :
Given, The outer circumference of the circular race track = 528 metre
Width of track = 14 m
Cost of levelling = Rs. 10 per sq. metre
Let the outer radius be $r$.
So, $2 \pi r = 528$
⇒ $r=\frac{528\times 7}{2\times 22}$
⇒ $r=84$ metre
Inner radius = 84 – 14 = 70 metres
Area of track = $\pi (84)^2-\pi (70)^2$
$= \frac{22}{7}\times (84-70)(84+70)$
= 6776 sq. metres
Total lost of levelling = 10 × 6776 = Rs. 67,760
Hence, the correct answer is Rs. 67,760.
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