the period of sin( x+8x+27x+... n^3x) is
Answer (1)
27th Sep, 2020
Hello !
f(x)= sin [{n*(n+1)/2}^2x]
we already know that period of f(ax+b) is T/|a|.
so, since period of sin is 2pi, the period of f(x) will be 8pi/[n*(n+1)]^2
Hope this helped!
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