Question : The table given below shows the number of sharpeners sold by two shopkeepers A and B in 5 months.
| Shopkeeper | ||
| Months | A | B |
| R | 200 | 155 |
| S | 190 | 160 |
| T | 170 | 210 |
| U | 165 | 180 |
| V | 155 | 175 |
$P1$ = The total number of sharpeners sold by A.
$P2$ = The total number of sharpeners sold by B.
What is the value of $\frac{P1}{P2}$?
Option 1: 1
Option 2: 2
Option 3: 3
Option 4: 4
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Correct Answer: 1
Solution :
As per the given graph,
$P1$ (total sharpeners sold by A) = 200 + 190 + 170 + 165 + 155 = 880
$P2$ (total sharpeners sold by B) = 155 + 160 + 210 + 180 + 175 = 880
So, the value of $\frac{P1}{P2}$ = $\frac{880}{880}$ = 1
Hence, the correct answer is 1.
Related Questions
Question : The following table shows the number of children in each house of a society.
| Number of Children | Number of Houses |
| 0 | 4 |
| 1 | 10 |
| 2 | 19 |
| 3 | 3 |
What is the average number of children per house?
Option 1: 1.58
Option 2: 1.83
Option 3: 2.08
Option 4: 1.33
Question : Directions: In the following question, select the missing number from the given responses.
| 1 | 3 | 7 |
| 2 | 4 | 4 |
| 4 | 5 | 9 |
| 3 | 2 | 3 |
| 50 | 70 | ? |
Option 1: 23
Option 2: 115
Option 3: 118
Option 4: 220
Question : Directions: Find the missing number.
| 3 | 4 | 64 |
| 2 | 3 | 9 |
| 3 | 2 | 8 |
| 9 | 2 | ? |
Option 1: 216
Option 2: 512
Option 3: 128
Option 4: 1024
Question : Directions: In the following question, select the missing number from the given responses.
| 2 | 4 | 5 | 3 | ||
| 3 | 3 | 3 | 6 | ? | 6 |
| 1 | 2 | 1 | 6 |
Option 1: 5
Option 2: 2
Option 3: 3
Option 4: 1
Question : Direction: Study the table and answer the question.
| Height (in cm) | Number of girls |
| less than 140 | 4 |
| less than 145 | 11 |
| less than 150 | 29 |
| less than 155 | 40 |
| less than 160 | 46 |
| less than 165 | 51 |
The average height (in cm) of the girls whose heights are 155 cm and above is about:
Option 1: 158.7
Option 2: 159.8
Option 3: 160.4
Option 4: 162.6
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