Question : Two points P and Q are at the distance of $x$ and $y$, where $y>x$, respectively from the base of a building and on a straight line. If the angles of elevation on the top of the building from points P and Q are complementary, then what is the height of the building?
Option 1: $xy$
Option 2: $\sqrt\frac{y}{x}$
Option 3: $\sqrt\frac{x}{y}$
Option 4: $\sqrt{xy}$
Correct Answer: $\sqrt{xy}$
Solution :
Given: Two points P and Q are at the distance of $x$ and $y$, where $y>x$, respectively from the base of a building and on a straight line.
$\tan\ \theta =\frac{AB}{x}$--------(equation 1)
In $\triangle ABQ$,
$\tan\ (90°–\ \theta) =\frac{AB}{y}$
$⇒\cot\ \theta =\frac{AB}{y}$-------(equation 2)
From equation 1 and equation 2, we get,
⇒ $\frac{AB}{x}= \frac{y}{AB}$
⇒ $(AB)^2=xy$
$\therefore AB=\sqrt{xy}$
Hence, the correct answer is $\sqrt{xy}$.
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