My jee main 48.59 percentile I qualified jee advance for obc ncl qutoa?
Answer (1)
22nd Jan, 2019
Hello Aspirant
Use this formula to predict the rank:
Rank Formula = (100 - your total score) X 874469 /100.
On the basis of the rank only the cutoff for college is predicted.
If you have NTA score then go by following link to predict the rank:https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-rank-predictor/amp
If you want to know how the percentile is calculated then go through once the below link to get an idea about percentile:
https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-normalisation-process-how-scores-are-calculated/amp
If you have got rank below 224000 then your are eligible for jEE advance as per now (approx) results.
But the rank may differ from the official results and cutoff which were released on the month of April.
If you have any questions further let me know
Thank you!!!
Use this formula to predict the rank:
Rank Formula = (100 - your total score) X 874469 /100.
On the basis of the rank only the cutoff for college is predicted.
If you have NTA score then go by following link to predict the rank:https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-rank-predictor/amp
If you want to know how the percentile is calculated then go through once the below link to get an idea about percentile:
https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-normalisation-process-how-scores-are-calculated/amp
If you have got rank below 224000 then your are eligible for jEE advance as per now (approx) results.
But the rank may differ from the official results and cutoff which were released on the month of April.
If you have any questions further let me know
Thank you!!!
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