Question : The angles of elevation of the top of a tower from two points at a distance of 4 m and 9 m from the base of the tower and in the same straight line with it are complementary. The height of the tower is:
Option 1: 4 metres
Option 2: 7 metres
Option 3: 9 metres
Option 4: 6 metres
Correct Answer: 6 metres
Solution :
Given: The angles of elevation of the top of a tower from two points at a distance of 4 m and 9 m from the base of the tower.
$ \angle C$ and $ \angle D$ are complementary.
We know that $\tan\theta=\frac{\text{Perpendicular}}{\text{Base}}$ and $\tan (90°–\theta)=\cot\theta$.
From the figure, it is clear that in $\triangle ABC$, $\tan\theta =\frac{AB}{BC}$.
$\tan\theta =\frac{AB}{4}$
Similarly, in $\triangle ABD$, $\tan (90°–\theta) =\frac{AB}{BD}$.
⇒ $\cot\theta =\frac{AB}{9}$
⇒ $\frac{1}{\tan\theta} =\frac{AB}{9}$
Substitute the value of $\tan\theta =\frac{AB}{4}$ in above equation, we get,
$\frac{4}{AB} =\frac{AB}{9}$
⇒ $AB^2=9×4$
⇒ $AB=\sqrt{36}=6 \ m$
Hence, the correct answer is 6 metres.
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