Question : There are 24 peaches, 36 apricots, and 60 bananas, and they have to be arranged in several rows in such a way that every row contains the same number of fruits of only one type. What is the minimum number of rows required for this to happen?
Option 1: 12
Option 2: 9
Option 3: 10
Option 4: 6
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Correct Answer: 10
Solution :
Minimum number of rows = Maximum number of fruits in a line
HCF of 24 peaches, 36 apricots, and 60 bananas = HCF of 24, 36, 60 = 12
Minimum number of rows = $\frac{24}{12} +\frac{36}{12} +\frac{60}{12}$ = (2 + 3 + 5) = 10
Hence, the correct answer is 10.
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