Question : The sides of a triangle are in the ratio 7 : 9 : 12. The difference between the lengths of the largest and smallest sides is 15 cm. The length of the largest side would be (in cm):
Option 1: 36
Option 2: 12
Option 3: 60
Option 4: 24
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
Correct Answer: 36
 
  Solution :
 
 Given: The sides of a triangle are in the ratio of 7 : 9 : 12.
 
  Let the sides of the triangle be $7x, 9x$, and $12x$.
  
  According to the question,
  
  $12x -7x = 15$
  
  ⇒ $5x = 15$
  
  ⇒ $x = \frac{15}{5} = 3$
  
  Largest side $=12x = 12 × 3= 36$ cm
  
  Hence, the correct answer is 36.
 
Related Questions
Know More about
Staff Selection Commission Combined High ...
Application | Eligibility | Admit Card | Answer Key | Preparation Tips | Result | Cutoff
Get Updates BrochureYour Staff Selection Commission Combined Higher Secondary Level Exam brochure has been successfully mailed to your registered email id “”.
 
																   
																 
								 
              
              




 
                
             
                    
                 
								 
								 
								 
								 
								