School of Business, UPES Dehradun All Questions

Hello!

Let us consider the first statement. The train starts from rest and acquires a speed v. So, initial velocity is 0 and final velocity is v.

We know that for uniform motion,

v = u + at. Here a = α .

Therefore,

v = u + α t

Since u = 0,

v = α t

α = v/t

Let t = t1

Thus

α  = v/t1 ..........(1)

Also, v^2 - u^2 = 2as

Since a = α, u = 0 and s = s1 is the distance travelled

v^2 = 2 α s1 ...........(2)

From (1) and (2), equating the values of  α, we get

s1 = v t1/2 ............(I)

Before it comes to stop,

v = u + at

Since it comes to stop, v =0; also here, a = β

Thus

0 = u + βt

Putting t = t2

0 = u + β t2

Now, the final velocity when the train starts from rest and the initial velocity before the train comes to rest are the same.

That is, u = v

Therefore,

0 = v + β t2

β = -v/t2 .............(3)

Also, v^2 - u^2 = 2as

Since a = β, final velocity v = 0 (as the train comes to a stop) and s = s2 is the distance travelled,

0 - u^2 = 2 β s2

We know that u = v. Thus,

-v^2 = 2 β s2 ........(4)

From (3) and (4), equating the values of β , we get

s2 = v t2/2 ............(II)

The average velocity can be calculated by

Avg. Velo. =  Total Distance Travelled/Total Time Taken

=  s1+s2/t1+t2

Substituting the values of s1 and s2 from (I) and (II),

Avg. Velo. =  (vt1/2 + vt2/2) / t1+t2

=   v/2 (t1+t2) /(t1+t2)

= v/2

Thus, the average velocity is v/2 .

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Hi Aspirant,

As per your cutoff score and previous year cutoff, the colleges you will get as per your cutoff score in Computer science are:-

Alagappa Chettair Government College of Engineering and Technology, Sivagangai

Sri Sairam Enginering College, Kancheepuram

Government College of Engineering, Thirunelveli

PA College of Engineering and Technology, Coimbatore

Srl Venkateswara College of Engineering, Kancheepuram

St. Josephs College of Engineering , Kancheepuram

Sona College of Technology

To know more about your other colleges check out this college predictor link:

https://engineering.careers360.com/tnea-college-predictor

Basically ICAS ( International center for Applied Sciences ) is one of the smallest bodies of Manipal University. Many Students do confuse it to be a part of MIT, but it isn't.

I would suggest you to please do not take up this program. If you want to go abroad for your studies and try for MS after your General B.tech from Manipal or any other University you want to take admission in.

All the best!!

Hi Rajnandini,

This is not there, if you will search for UPPSC or UPPCS, you will get search result as 'Uttar Pradesh Public Service Commission'. If you are not able get this, then refer to the links mentioned below.

Official website - http://uppsc.up.nic.in/

Refer here for more info - https://competition.careers360.com/articles/up-pcs

Feel free to ask doubts in the Comment Section.

I hope this information helps you.

Good Luck!