School of Business, UPES Dehradun All Questions

Hello Aspirant,

Yes it do comes under NEET.

Perhaps, the Commissioner for Entrance Examinations (CEE) Kerala confirmed the list of medical and allied courses that  come under  the ambit of  NEET  -UG. Candidates who are planning to study courses such as  B.Sc Agriculture  ,  Bachelor of Fisheries  Sciences,  B.Sc  Forestry etc will be required to clear the  NEET  exam.

This may help.

Happy learning!

Hello

Your admission in MBBS is solely dependent on the marks obtained by you in NEET examination there's no role of marks obtained by you in class 12th board examination in getting a seat in a medical college.

The only role of your class 12th board examination marks is to make you eligible for neet examination and that's it .

So, you should prepare well for your neet examination as admission completely based on it, go through NEET mock test , previous year papers , it will let you know your preparation level and and weak areas so that you can work on them and perform well in your examination .

Thankyou

Generally cutoffs changes every year it depends upon various factors like, difficulty level of the entrance exam, number of students applying for the exam, performance of the students in the exam, etc.

But in general if you consider previous year cutoffs then you can easily get CSE in Reva as the closing cutoffs was around 25300, last year.

All the best!!

V=0+αt1

t1=V/α

Similarity, t2=V/β

or t1+t2=V/α+V/β

=αβV/(α+β)

Hello!

Let us consider the first statement. The train starts from rest and acquires a speed v. So, initial velocity is 0 and final velocity is v.

We know that for uniform motion,

v = u + at. Here a = α .

Therefore,

v = u + α t

Since u = 0,

v = α t

α = v/t

Let t = t1

Thus

α  = v/t1 ..........(1)

Also, v^2 - u^2 = 2as

Since a = α, u = 0 and s = s1 is the distance travelled

v^2 = 2 α s1 ...........(2)

From (1) and (2), equating the values of  α, we get

s1 = v t1/2 ............(I)

Before it comes to stop,

v = u + at

Since it comes to stop, v =0; also here, a = β

Thus

0 = u + βt

Putting t = t2

0 = u + β t2

Now, the final velocity when the train starts from rest and the initial velocity before the train comes to rest are the same.

That is, u = v

Therefore,

0 = v + β t2

β = -v/t2 .............(3)

Also, v^2 - u^2 = 2as

Since a = β, final velocity v = 0 (as the train comes to a stop) and s = s2 is the distance travelled,

0 - u^2 = 2 β s2

We know that u = v. Thus,

-v^2 = 2 β s2 ........(4)

From (3) and (4), equating the values of β , we get

s2 = v t2/2 ............(II)

The average velocity can be calculated by

Avg. Velo. =  Total Distance Travelled/Total Time Taken

=  s1+s2/t1+t2

Substituting the values of s1 and s2 from (I) and (II),

Avg. Velo. =  (vt1/2 + vt2/2) / t1+t2

=   v/2 (t1+t2) /(t1+t2)

= v/2

Thus, the average velocity is v/2 .

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Vicky, NEET is the entrance examination for admission to MBBS,BDS, Ayush and Veterinary courses across India. JEE Mains is the entrance examination for admission to Engineering and Technological courses in Government, Private Engineering Colleges, NITs, IIITs and GFTIs. JEE Advanced is the gateway for admission to Engineering and Technological courses to IITs. But B.Des is the entrance examination for admission to Fashion Designing Courses. It is a different course all together when compared to NEET or JEE.