What is total number of isomers in square planar complex M[(F) (Cl) (SCN) (NO2)] ? asked in jee 2019.
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bro,
it has 3 geometrical isomers
no2 and scn are ambedient nucleophile
therefore total isomers are 3*2*2=12
....easy
Hello yash.
For any square planar complex of type MABCD,there are no optical isomers but only geometrical isomers.There will be a total of 3 isomers.The three isomers place A trans to C,A trans to B,and A trans to D.There won't be any chiral isomer because there is always a plane of symmetry present in the square planar complex.Hence,a total of 3 isomers.
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