What is the cutoff for jee mains 2019 for computer science branch?
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For every college cuttoff changes ,
and every year cutoff changes so we can't predict accurately but according to previous years cutoff
There is very tough competition for cs branch
And one requires very good rank get into the good college
Here is college cutoffs of previous years you will get some idea from it
https://www.google.com/amp/s/engineering.careers360.com/articles/nits-cutoff-for-btech-computer-science-engineering/amp
Good luck.
Hi Prem,
AIT Pune has not yet released the merit list for 2019, but I can provide you the cutoff of previous years from which you can get an idea.
In 2016,
JEE Mains Cutoff Rank- 55,132 (CSE)
In 2017,
JEE Mains Cutoff Rank- 59,627 (CSE)
In 2018,
JEE Mains Cutoff Rank- 55,132 (CSE)
If you have secured a rank under 60,000, you have a decent chance of selection.
All the best!!!!
Cut off of each college is different .
I am providing you a link where all the Jee main colleges cut off .
https://engineering.careers360.com/articles/nits-cutoff-for-top-btech-branches/amp
Thanks
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