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    Cube: Definition in Math, Reasoning Questions, Examples
    • Reasoning
    • Cube: Definition in Math, Reasoning Questions, Examples

    Cube: Definition in Math, Reasoning Questions, Examples

    Hitesh SahuUpdated on 14 Apr 2026, 08:07 PM IST

    Think of a dice or a Rubik’s cube - each face, edge, and corner holds important information that can be used to solve logical problems. Cube-based questions in reasoning are built around this idea, where you analyze how a cube looks after cuts, folds, or color changes. These questions test your spatial visualization skills and understanding of three-dimensional structures. Cube reasoning is commonly asked in competitive exams like SSC, banking, and defence exams. In this article, you will learn the basic definition of a cube in mathematics, important concepts related to cube-based reasoning questions, and examples to help you solve them with clarity and confidence.

    This Story also Contains

    1. Cube: Structure of a Cube
    2. What is a Cube in Mathematics
    3. Key Concepts to Understand in Cube Reasoning
    4. Types of Questions Asked in Cube Reasoning
    5. Related Formulas for Cube Problems
    6. Non Verbal Reasoning Topics
    7. Questionwise Weightage of Cube in Competitive Exams
    8. Practice Questions For Cutting a Cube and Counting Smaller Cubes
    9. Practice Questions For Counting Coloured Cubes
    10. Step-by-Step Approach to Solve Cube Questions
    11. Shortcut Tricks to Solve Cube Questions Quickly
    12. Best Books for Cube Reasoning Preparation
    13. Important Formulas for Cube Reasoning (Quick Revision Table)
    14. Verbal Reasoning Topics
    Cube: Definition in Math, Reasoning Questions, Examples
    Cube: Definition in Math, Reasoning Questions, Examples

    Cube: Structure of a Cube

    A cube is a 3D figure with three sides, length, breadth and height, where all the sides are equal. A cube has 6 faces, 8 vertices, and 12 edges. The faces of the cube are square-shaped, and each face meets at a right angle. Each of the faces meets the other four faces, and one face is opposite. Each of the vertices meets three faces and three edges. The edges and faces opposite to each other are parallel.

    What is a Cube in Mathematics

    A cube is a three-dimensional geometric shape that plays an important role in both mathematics and reasoning-based problems. It is commonly used in aptitude and logical reasoning questions where candidates are required to visualize cuts, colors, or positions on different faces. Cube-based questions test spatial understanding, visualization skills, and logical thinking, making them a frequent topic in competitive exams.

    Definition of cube in math

    A cube is a solid figure in which all sides are equal and all angles are right angles.

    • It is a three-dimensional shape with equal length, width, and height
    • All faces of a cube are perfect squares
    • It is also known as a regular hexahedron
    • Widely used in geometry and reasoning questions

    Understanding this definition is essential for solving cube-based problems in exams.

    Basic properties of a cube

    A cube has several unique properties that make it easy to analyze in reasoning questions.

    • All edges of a cube are equal in length
    • Each face is identical in shape and size
    • All angles in a cube are 90 degrees
    • Opposite faces are parallel to each other

    These properties help in solving cube-related reasoning questions accurately.

    Faces, edges, and vertices explained

    To understand cube problems, it is important to know its structural elements.

    • A cube has 6 faces, each of which is a square
    • It has 12 edges, where two faces meet
    • It has 8 vertices or corners where three edges meet
    • Each vertex connects three faces

    Knowing these basics is crucial for solving cube cutting and painted cube questions.

    Importance in reasoning and aptitude

    Cube concepts are widely used in reasoning and aptitude sections of competitive exams.

    • They test spatial visualization and 3D understanding
    • Common in questions related to dice, cutting, and painting
    • Help improve logical thinking and problem-solving ability
    • Often appear as moderate-level scoring questions

    Because of their practical and visual nature, cube questions are an important part of reasoning preparation for exams like SSC, banking, MBA, and defence tests.

    Key Concepts to Understand in Cube Reasoning

    Cube reasoning requires a clear understanding of structure and spatial relationships. These concepts help in solving cube-based questions in aptitude and logical reasoning.

    Faces, edges, and vertices relationships

    • A cube has 6 faces, 12 edges, and 8 vertices
    • Each vertex connects three edges and three faces
    • Understanding this relationship is essential for solving cube problems

    Opposite faces and adjacency in cube

    • Opposite faces never share an edge
    • Adjacent faces share a common edge
    • Knowing this helps in solving dice and cube-based questions

    Color distribution on cube faces

    • Some questions involve colored faces of a cube
    • You need to track how colors appear after cuts
    • Helps in identifying painted and unpainted faces

    Number of smaller cubes after cutting

    • When a cube is cut, it forms smaller cubes
    • The number depends on how many cuts are made
    • Important for solving cube cutting questions

    Types of Questions Asked in Cube Reasoning

    There are several types of questions that have been seen from the topic cube -

    1. Cutting of a cube and counting of smaller cubes

    2. Counting of coloured cubes

    Let’s discuss these types and cube reasoning tricks in detail with the help of examples -

    1. Cutting of a Cube and Counting of Smaller Cubes

    In these types of problems, a bigger cube is divided into smaller cubes by making the required number of cuts on different faces. Each smaller cube is of equal length.

    To understand the concept, let’s assume that the bigger cube of length ‘L1’ is cut from different faces to form smaller cubes of length ‘L2’.

    If we divide the length of a bigger cube by the length of the smaller cubes, we will get the number of parts (of each face) in which the cube is divided, and that is denoted by ‘n’.

    ∴ n = L1/L2

    So, the total number of cuts to be made = 3 × (n - 1)

    The total number of smaller cubes formed due to the division of a cube = (n)3

    Example: Suppose a cube of length 27 cm is cut into smaller cubes of length 3 cm. How many cuts will be made and how many smaller cubes will be formed?

    Answer: n = L1/L2 = 27/3 = 9

    ∴ Total number of cuts = 3 × (n - 1) = 3 × (9 - 1) = 3 × 8 = 24

    ∴ Total number of smaller cubes = (n)3 = (9)3 = 729

    2. Counting of Coloured Cubes

    In these types of problems, the given cube will be painted on all its surfaces with any colour. So, here, we have to find the number of coloured cubes based on the number of painted surfaces of smaller cubes. When we cut a painted cube to form smaller cubes, we will get different types of painted cubes based on the number of painted surfaces. We have two categories of coloured cubes:

    (I) Single-Coloured Cube

    Here, all the surfaces of the cube are painted with only one colour. When the cube is cut into smaller cubes, we will get different types of cubes based on the number of painted surfaces. They are as follows:

    Corner cube (3-Faces coloured) - When the painted cube is cut to form smaller cubes, the maximum number of the painted surfaces of smaller cubes can be 3. These types of cubes are formed at the corner of the bigger cube, that’s why, these cubes are also known as corner cubes. Thus, all the corner cubes are painted on 3 surfaces. As we know, there are a total of 8 corners.

    So, the number of smaller cubes of which 3 surfaces are painted = 8

    Middle cubes (2-Faces coloured) - When the painted cube is cut, the formed smaller cubes are also painted. These types of cubes are formed at the middle of the edges of the cube, that’s why, these cubes are also known as middle cubes.

    The number of smaller cubes of which 2 surfaces are painted = 12 × (n - 2)

    Central cubes (1-Face coloured) - When the painted cube is cut, the formed smaller cubes are also painted. These types of cubes are formed at the centre of the faces of the cube, that’s why, these cubes are also known as central cubes.

    The number of smaller cubes of which 1 surface is painted = 6 × (n - 2)2

    Inner Central cubes (0-Faces coloured) - When the painted cube is cut, the formed smaller cubes are also painted. These types of cubes are formed inside the centre of the cube, that’s why, these cubes are also known as inner central cubes.

    The number of smaller cubes of which 0 surface is painted = (n - 2)3

    Example: A bigger cube with all surfaces painted yellow is cut into 27 smaller cubes of equal size. How many smaller cubes are there which have 3 surfaces painted, 2 surfaces painted, 1 surface painted, and no surface painted?

    Answer: Total smaller cubes = 27

    ⇒ (n)3 = 27 ⇒ n = 3

    Total number of cubes with 3 surfaces painted = 8
    Total number of cubes with 2 surfaces painted = 12 × (n - 2) = 12 × (3 - 2) = 12 × 1 = 12
    Total number of cubes with 1 surface painted = 6 × (n - 2)2 = 6 × (3 - 2)2 = 6 × 1 = 6
    Total number of cubes with 0 surfaces painted = (n - 2)3 = (3 - 2)3 = 1

    (II) Multi-Coloured Cube

    Here, all the surfaces of the cube are painted with different colours. When the cube is cut into smaller cubes, we will get different types of cubes based on the number of painted surfaces. They are as follows:

    Corner Cube (3-Faces coloured) - When the painted cube is cut to form smaller cubes, the maximum number of the painted surfaces of smaller cubes can be 3. These types of cubes are formed at the corner of the bigger cube, that’s why, these cubes are also known as corner cubes. Thus, all the corner cubes are painted on 3 surfaces. As we know, there are a total of 8 corners.

    So, the number of smaller cubes of which 3 surfaces are painted = 8

    But here, if we talk about the painted surfaces with a particular colour, then we can simply refer to the picture of the cube to identify the painted surface of the cube with a specific colour.

    Middle Cubes (2-Faces coloured) - When the painted cube is cut, the formed smaller cubes are also painted. These types of cubes are formed at the middle of the edges of the cube, that’s why, these cubes are also known as middle cubes.

    The number of smaller cubes of which 2 surfaces are painted = 12 × (n - 2)

    But here, if we talk about the painted surfaces with a particular colour, then we can simply refer to the picture of the dice. 2-faces coloured cubes depend on the edges of the cube. Multiply (n - 2) by the number of required edges to identify the painted surfaces of the cube with a specific colour.

    Central Cubes (1-Face coloured) - When the painted cube is cut, the formed smaller cubes are also painted. These types of cubes are formed at the centre of the faces of the cube, that’s why, these cubes are also known as central cubes.

    The number of smaller cubes of which 1 surface is painted = 6 × (n - 2)2

    But here, if we talk about the painted surfaces with a particular colour, then we can simply refer to the picture of the dice. 1-face coloured cubes depend on the faces of the cube. Multiply (n - 2)2 by the number of required faces to identify the painted surfaces of the cube with a specific colour.

    Inner Central Cubes (0-Faces coloured) - When the painted cube is cut, the formed smaller cubes are also painted. These types of cubes are formed inside the centre of the cube, that’s why, these cubes are also known as inner central cubes.

    The number of smaller cubes of which 0 surface is painted = (n - 2)3

    Example: Two adjacent surfaces of a cube are painted red, two other adjacent faces are blue, and two remaining adjacent faces are painted green. Now it is cut into 125 smaller cubes, then how many smaller cubes have 2 surfaces painted with red and green colour, and 1 surface painted with blue colour?

    Answer: Total smaller cubes = 125

    ⇒ (n)3 = 125 ⇒ n = 5

    Cube

    Total number of cubes with 2 surfaces painted (Red + Green), Here, if we check the figure, the edges that have red and green faces at their sides, there are only 3 such edges.
    Thus, the total number of required cubes = 3 × (n - 2) = 3 × (5 - 2) = 3 × 3 = 9
    Total number of cubes with 1 surface painted (Blue), here, if we check the figure, 2 faces that are painted blue.
    Thus, the total number of required faces = 2 × (n - 2)2 = 2 × (5 - 2)2 = 2 × 9 = 18

    Related Formulas for Cube Problems

    This section covers the key formulas and standard concepts used in cube-based reasoning questions, helping you quickly calculate values related to cuts, painted faces, and smaller cubes for faster problem-solving.

    Number of smaller cubes after cuts

    • If a cube is divided into n parts, total smaller cubes = $n^3$

    Painted faces logic

    • Cubes can have 0, 1, 2, or 3 faces painted
    • Based on their position (corner, edge, or center)

    Corner, edge, and center cube formulas

    • Corner cubes = 8
    • Edge cubes = $12(n - 2)$
    • Face center cubes = $6(n - 2)^2$
    • Inner cubes = $(n - 2)^3$

    Non Verbal Reasoning Topics

    This section includes figure-based and visual reasoning topics that focus on patterns, shapes, and logical analysis without the use of words.

    Questionwise Weightage of Cube in Competitive Exams

    The number of questions based on the cube varies from exam to exam -
    1) Questions asked in SSC exams i.e. SSC MTS, SSC CGL, SSC CHSL, SSC CPO, Steno - 2 to 3 questions.
    2) Questions asked in the RRB exam i.e. Group D, NTPC, JE, ALP etc - 2 to 3 questions.
    3) Questions asked in Banking exams, Bank PO, Bank Clerk - 1 to 2 questions.
    4) The candidates must practice cube reasoning questions pdf or questions on cube reasoning, to ace the topic of cube reasoning.

    Note: Practice cube reasoning questions with answers of each type given below.

    Practice Questions For Cutting a Cube and Counting Smaller Cubes

    Q1. Directions: A bigger cube of length 64 cm is cut into smaller cubes of length 8 cm. What is the total number of cubes made?

    A) 27

    B) 125

    C) 512 (Correct)

    D) 64

    Solution:
    Length of bigger cube = 64 cm, Length of each smaller cube = 8 cm
    Thus, n = 64/8 = 8
    So, the total number of cubes made = (n)3 = (8)3 = 512
    Hence, the third option is correct.

    Q2. Directions: A bigger cube is cut into 125 smaller cubes. How many cuts are required to form these smaller cubes?

    A) 20

    B) 5

    C) 10

    D) 12 (Correct)

    Solution:
    The total number of cubes made = 125
    ⇒ (n)3 = 125 ⇒ n = 5
    Total number of cuts = 3 × (n - 1) = 3 × (5 - 1) = 3 × 4 = 12
    Hence, the fourth option is correct.

    Q3. Directions: A bigger cube of length 48 cm is cut into smaller cubes of length 8 cm. What is the total number of cubes made?

    A) 64

    B) 216 (Correct)

    C) 125

    D) 40

    Solution:
    Length of bigger cube = 48 cm, Length of each smaller cube = 8 cm
    Thus, n = 48/8 = 6
    So, the total number of cubes made = (n)3 = (6)3 = 216
    Hence, the second option is correct.

    Q4. Directions: If a number of smaller cubes are taken out from a bigger cube, each side is ¼ the size of the original cube’s side. What is the total number of smaller cubes made?

    A) 60

    B) 64 (Correct)

    C) 25

    D) 20

    Solution:
    Let the length of the bigger cube = x cm and the length of each smaller cube = x/4 cm
    Thus, n = x/(x/4) = 4
    So, the total number of cubes made = (n)3 = (4)3 = 64
    Hence, the second option is correct.

    Q5. Directions: If a number of smaller cubes are taken out from a bigger cube, each side is 1/7 the size of the original cube’s side. What is the total number of smaller cubes made?

    A) 343 (Correct)

    B) 64

    C) 125

    D) 150

    Solution:
    Let the length of the bigger cube = x cm, and the length of each smaller cube = x/7 cm
    Thus, n = x/(x/7) = 7
    So, the total number of cubes made = (n)3 = (7)3 = 343
    Hence, the first option is correct.

    Practice Questions For Counting Coloured Cubes

    Q1. A 12 cm coloured cube is cut into 2 cm smaller cubes. How many cubes have 2 surfaces painted and 1 surface painted?

    A) 48, 96 (Correct)

    B) 48, 90

    C) 56, 96

    D) 36, 94

    Answer:
    Length of original cube = 12 cm, Length of smaller cubes = 2 cm
    So, n = 12/2 = 6
    Total number of cubes with 2 surfaces painted = 12 × (n - 2) = 12 × (6 - 2) = 12 × 4 = 48
    Total number of cubes with 1 surface painted = 6 × (n - 2)2 = 6 × (6 - 2)2 = 6 × 16 = 96
    Hence, the first option is correct.

    Q2. A 25 cm coloured cube is cut into 5 cm smaller cubes. How many cubes have 3 surfaces painted, 2 surfaces painted and 1 surface painted?

    A) 8, 24, 54

    B) 8, 36, 45

    C) 8, 36, 54 (Correct)

    D) 8, 48, 36

    Answer:
    Length of original cube = 25 cm, Length of smaller cubes = 5 cm
    So, n = 25/5 = 5
    Total number of cubes with 3 surfaces painted = 8
    Total number of cubes with 2 surfaces painted = 12 × (n - 2) = 12 × (5 - 2) = 12 × 3 = 36
    Total number of cubes with 1 surface painted = 6 × (n - 2)2 = 6 × (5 - 2)2 = 6 × 9 = 54
    Hence, the third option is correct.

    Q3. A bigger cube with all surfaces painted yellow is cut into 27 smaller cubes of equal size. How many cubes are there which have only one surface painted?

    A) 1

    B) 6 (Correct)

    C) 8

    D) 10

    Solution:
    Total number of smaller cubes = 27
    ⇒ Total number of smaller cubes = (n)3 ⇒ (n)3 = 27 ⇒ n = 3
    Total number of cubes with 1 surface painted = 6 × (n - 2)2 = 6 × (3 - 2)2 = 6 × 1 = 6
    Hence, the second option is correct.

    Q4. A cube of white material is painted black on all its surfaces. If it is cut into 216 smaller cubes of the same size, then how many cubes will have 2 surfaces painted black?

    A) 96

    B) 56

    C) 64

    D) 48 (Correct)

    Solution:
    Total number of smaller cubes = 216
    ⇒ Total number of smaller cubes = (n)3 ⇒ (n)3 = 216 ⇒ n = 6
    Total number of cubes with 2 surface painted = 12 × (n - 2) = 12 × (6 - 2) = 12 × 4 = 48
    Hence, the fourth option is correct.

    Q5. A coloured cube is cut into 343 smaller cubes of the same size, then how many cubes will have at least 2 surfaces painted?

    A) 48

    B) 68 (Correct)

    C) 8

    D) 40

    Solution:
    Total number of smaller cubes = 343
    ⇒ Total number of smaller cubes = (n)3 ⇒ (n)3 = 343 ⇒ n = 7
    Total number of cubes with at least 2 surfaces painted = Cubes with 2 surfaces painted + Cubes with 3 surfaces painted = (12 × (n - 2)) + 8 = (12 × (7 - 2)) + 8 = (12 × 5) + 8 = 60 + 8 = 68
    Hence, the second option is correct.

    Q6. A coloured cube is cut into 125 smaller cubes of the same size, then how many cubes will have at most 2 surfaces painted?

    A) 117 (Correct)

    B) 124

    C) 96

    D) 105

    Solution:
    Total number of smaller cubes = 125
    ⇒ Total number of smaller cubes = (n)3 ⇒ (n)3 = 125 ⇒ n = 5
    Total number of cubes with at most 2 surfaces painted = Cubes with 2 surfaces painted + Cubes with 1 surfaces painted + Cubes with no surface painted = (12 × (n - 2)) + (6 × (n - 2)2) + ((n - 2)3) = (12 × (5 - 2)) + (6 × (5 - 2)2) + ((5 - 2)3) = (12 × 3) + (6 × 9) + (27) = 117
    Hence, the first option is correct.

    Q7. There is a bigger cube of 12 cm. 2 adjacent surfaces of it are painted red, 2 other adjacent surfaces are painted yellow, 1 surface is painted blue, and 1 surface is painted green. Now it is cut into smaller cubes of 2 cm, then how many smaller cubes are there which have only 2 surfaces painted with red and blue colour?

    A) 48

    B) 8 (Correct)

    C) 24

    D) 32

    Solution:
    Length of bigger cube = 12 cm, Length of smaller cube = 2 cm
    So, n = 12/2 = 6
    Now, we have to consider the smaller cubes whose one surface is painted red and the other is painted blue, as shown in the diagram below:


    Figure of cube

    So, according to the above diagram, there are only 2 such edges where these required cubes are formed.
    The number of smaller cubes which have only 2 surfaces painted with red and blue colour = 2 × (n - 2)
    = 2 × (6 - 2) = 2 × 4 = 8
    Hence, the second option is correct.

    Q8. A bigger coloured cube is cut into 125 smaller cubes of 8 cm3, then what is the length of the bigger cube?

    A) 40 cm

    B) 20 cm

    C) 5 cm

    D) 10 cm (Correct)

    Solution:
    Total number of smaller cubes = 125
    The total number of smaller cubes = (n)3 ⇒ (n)3 = 125 ⇒ n = 5
    The volume of each smaller cube = 8 cm3
    So, the length of the smaller cube = 2 cm
    Let the length of the bigger cube be L cm.
    So, n = L/2 ⇒ 5 = L/2 ⇒ L = 10 cm
    Hence, the fourth option is correct.

    Q9. Two adjacent surfaces of a bigger cube are painted red, 1 surface is painted blue and the remaining 3 surfaces are painted yellow. Now, it is cut into 216 smaller cubes. How many smaller cubes have only 1 surface painted with a yellow colour?

    A) 48 (Correct)

    B) 32

    C) 16

    D) 12

    Solution:
    Total number of smaller cubes = 216
    The total number of smaller cubes = (n)3 ⇒ (n)3 = 216 ⇒ n = 6
    Here, we have to determine the number of smaller cubes that have 1 surface painted with yellow colour.
    Yellow painted surfaces are 3,
    The number of cubes that have only 1 surface painted with yellow colour = 3 × (n - 2)2 = 3 × (6 - 2)2 = 3 × 16 = 48
    Hence, the first option is correct.

    Q10. Four surfaces of a bigger cube are painted red, and the remaining 2 surfaces are painted yellow. Now, it is cut into 64 smaller cubes. How many smaller cubes have only 1 surface painted with a red colour?

    A) 8

    B) 32

    C) 16 (Correct)

    D) 12

    Solution:
    Total number of smaller cubes = 64
    The total number of smaller cubes = (n)3 ⇒ (n)3 = 64 ⇒ n = 4
    Here, we have to determine the number of smaller cubes that have 1 surface painted with red colour.
    Red painted surfaces are 4,
    The number of cubes that have only 1 surface painted with red colour = 4 × (n - 2)2 = 4 × (4 - 2)2 = 4 × 4 = 16
    Hence, the third option is correct.

    Step-by-Step Approach to Solve Cube Questions

    A structured method helps in solving cube reasoning questions accurately.

    Understand the cube structure

    • Identify faces, edges, and vertices
    • Visualize the cube clearly

    Identify the number of cuts

    • Determine how many times the cube is divided
    • Helps in calculating smaller cubes

    Apply formulas correctly

    • Use standard cube formulas
    • Avoid calculation errors

    Analyze painted and unpainted faces

    • Identify cubes based on painted sides
    • Classify them into corner, edge, or center cubes

    Shortcut Tricks to Solve Cube Questions Quickly

    Shortcut techniques help in saving time in exams.

    Use standard cube formulas

    • Memorize basic formulas for quick calculation
    • Avoid solving from scratch

    Focus on corner, edge, and center cubes

    • Divide the problem into categories
    • Solve each type separately

    Avoid unnecessary calculations

    • Use logic instead of lengthy steps
    • Simplify the problem wherever possible

    Practice visualization techniques

    • Improve 3D thinking skills
    • Helps in solving questions mentally without drawing

    Best Books for Cube Reasoning Preparation

    This section lists the most recommended books to help you build strong concepts and practice cube reasoning questions effectively for competitive exams.

    Book NameAuthorKey FeaturesBest For
    A Modern Approach to Verbal & Non-Verbal ReasoningR.S. AggarwalCovers cube, dice, and spatial reasoning with diagrams and practiceBeginners and SSC aspirants
    Analytical ReasoningM.K. PandeyIncludes puzzle-based and visualization questionsBanking and MBA exams
    A New Approach to Reasoning Verbal & Non-VerbalB.S. SijwaliProvides shortcut techniques and concept clarityBeginners to intermediate level
    Logical ReasoningArun SharmaAdvanced level reasoning and visualization questionsMBA entrance exams
    Magical Book on PuzzlesK. KundanHelps improve spatial reasoning and speedPractice and speed improvement
    SSC Reasoning Chapterwise Solved PapersKiran PublicationsPrevious year cube questions with solutionsSSC exam preparation

    Important Formulas for Cube Reasoning (Quick Revision Table)

    This section provides key formulas and concepts related to cube problems, helping you quickly revise and solve questions with accuracy.

    Concept / FormulaExpressionUse Case
    Total smaller cubes$n^3$When cube is divided into n parts
    Corner cubes$8$Always fixed
    Edge cubes$12(n - 2)$Cubes on edges
    Face center cubes$6(n - 2)^2$Cubes on faces
    Inner cubes$(n - 2)^3$Completely inside cubes
    Cubes with 3 faces painted$8$Corner cubes
    Cubes with 2 faces painted$12(n - 2)$Edge cubes
    Cubes with 1 face painted$6(n - 2)^2$Face center cubes
    Cubes with no paint$(n - 2)^3$Inner cubes

    Key Takeaways

    • Series reasoning is based on pattern recognition, not fixed formulas
    • Cube reasoning uses standard formulas and spatial understanding
    • Practice helps in improving speed and accuracy
    • Use elimination techniques to solve questions faster

    Verbal Reasoning Topics

    This section covers important topics based on words, letters, and language patterns that are essential for reasoning sections in exams. For verbal reasoning, read the topics below:

    Frequently Asked Questions (FAQs)

    Q: Which exams include questions related to the cube?
    A:

    The questions related to the cube are asked in various competitive exams such as SSC, Bank PO, Bank Clerk, Railway, Defence, UPSC, State PCS, etc.

    Q: What is the weightage of the cube questions in the exams?
    A:

    In the SSC exams around 2-3 questions have been asked every year whereas in other exams like Railways, CUET or Defence mostly 1-2 questions have been asked.

    Q: What are the important formulas in cube reasoning?
    A:

    Key formulas include total cubes = $n^3$, edge cubes = $12(n-2)$, and inner cubes = $(n-2)^3$.

    Q: How much time should be spent on one cube question?
    A:

    Most cube questions can be solved within 1–2 minutes with proper practice.

    Q: What type of questions are asked from the topic cube?
    A:

    The questions asked from the topic cube are based on the cutting of the cube, counting of smaller cubes when the cube is being cut into smaller pieces, and counting of coloured cubes.

    Q: How to solve cube questions in reasoning?
    A:

    There are several types of questions that have been seen from the topic cube like Cutting of a cube and counting of smaller cubes or Counting of coloured cubes. To solve these types of questions follow the below points.
    1) Cutting of a cube or counting of smaller cubes: In these types of problems, a bigger cube is divided into smaller cubes by making the required number of cuts on different faces. Each smaller cube is of equal length. To understand the concept, let’s assume that the bigger cube of length ‘L1’ is cut from different faces to form smaller cubes of length ‘L2’. If we divide the length of a bigger cube by the length of the smaller cubes, we will get the number of parts (of each face) in which the cube is divided, and that is denoted by ‘n’. n = L1/L2
    So, the total number of cuts to be made = 3 × (n - 1)
    The total number of smaller cubes formed due to the division of a cube = (n)3       
    2) Counting of coloured cubes: In these types of problems, the given cube will be painted on all its surfaces with any colour. So, here, we have to find the number of coloured cubes based on the number of painted surfaces of smaller cubes. When we cut a painted cube to form smaller cubes, we will get different types of painted cubes based on the number of painted surfaces.
    For a detailed explanation, you must read the article above.      

    Q: What is the reasoning formula for a cube?
    A:

    The reasoning formula for a cube: A cube of side nnn painted on all sides which is uniformly cut into smaller cubes of dimension 111,

    1) Number of cubes with 0 side painted= (n-2) 3. 

    2) Number of cubes with 1 sides painted =6(n - 2) 2. 

    3) Number of cubes with 2 sides painted= 12(n-2)

    Q: How to solve a 3 dice problem?
    A:

    To solve a 3 dice problem follow the below steps:

    1) The formula which is used to solve is of probability which is equal to (Favorable outcomes/Total number of outcomes.)

    2) Now when three dice are thrown then the total number of outcomes = 63 = 216.

    3) Now the total number of outcomes = 216. The probability of not getting 3 on a single die = 5/6.

    4) Therefore the required probability is 91/216.

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