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    What is Percentile of 70 Marks in MAH CET BBA?

    What is Percentile of 70 Marks in MAH CET BBA?

    Tekumalla AvinashramUpdated on 07 Oct 2026, 12:37 PM IST

    In the MAH CET BBA exam, percentile scores reflect how a candidate performs compared to others. A percentile for 70 marks in MAH CET BBA typically corresponds to a 98-99 percentile range, based on previous years' trends. The BBA colleges accepting 70 marks in MAH CET BBA may shift each year depending on factors like exam difficulty, number of test-takers, and seat intake across participating institutes. Can candidates refer to the data below to draw a conclusion on whether 70 marks are enough for BBA admission through MAH CET?

    What is Percentile of 70 Marks in MAH CET BBA?
    What is Percentile of 70 Marks in MAH CET BBA?

    70 Marks in MAH CET 2027 Percentile

    Achieving 70 marks is considered a commendable score, placing you in the 98th to 99th percentile range. This performance is above average and opens doors to several reputable BBA colleges in Maharashtra.

    MAH CET Marks vs Percentile

    Check out the MAH BBA CET marks vs percentile based on previous year data below.

    MAH BBA CET Marks Vs Percentile (MH Candidates - 2026)

    Marks

    Percentile

    80+

    99.50 and above

    75-80

    99 and above

    65-75

    98-99

    55-70

    96-98

    50-55

    95-96

    48-50

    92-94

    40.5-47.5

    85-91

    30.5-40

    66-83

    25-30

    55-65


    Also Read: What is a good score in MAH BBA CET?

    MAH BBA Percentile Range and Rank

    Percentile Range

    Estimated Rank Range

    99-100

    1 - 1,000

    95-98

    1,001 - 5,000

    90-94

    5,001 - 10,000

    85-89

    10,001 - 15,000

    80-84

    15,001 - 20,000

    Also Read: MAH BBA CET Cutoff

    BBA Colleges Accepting 70 marks in MAH CET BBA

    The MAH BBA CET percentile is determined using a normalization method, which allows fair comparison among candidates across multiple test sessions. The formula used is: Percentile Score = 100 × (Number of candidates with normalized marks ≤ the candidate's marks / Total number of candidates)

    Some of the top institutes candidates can apply to are as follows:

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