Dr KN Modi University, Tonk All Questions

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For any IIM, you will need more than 95 percentile. IIM A has had the following percentiles as the minimum cut offs for 2019 across all Categories.

Hey there,

I hope you are safe and healthy.

I am providing you a link below. There you will find the answer to your question in a step-wise and a proper elaborative manner. I hope you understand the solution.

https://learn.careers360.com/ncert/question-using-the-method-of-integration-find-the-area-of-the-triangle-abc-coordinates-of-whose-vertices-are-a-2-0-b-4-5-and-c-6-3/

I hope you find it useful.

Hello student,

I hope you are doing well.

1). The three pairs of equal parts in two triangles ABC and BOD are:

CO = DO (given)

OA = OB (given)

Angle COA = Angle DOB ( As opposite angles are equal when two lines intersect)

2).  So by SAS congruency

Hi there,

I hope you are doing well. The language of your question is not clear but what I infer is that you have opted for wrong option and form has been submitted.

I would like to tell you that try contacting the concerned authority of the council to make

Hii Meghana,

It depends on the exam pattern . If the given question has partial marking then you will get partial marking in the above case . If there is no partial marking then you will loose marks, in some cases even there is a chance of negative marking also.

Hello aspirant,

Hope you are doing well.

As per your question regarding ICAR exam if you are eligible for exam then definitely you can give the ICAR exam. Here Eligibility mainly concerns with that you should have passed 10+2 with a minimum percentage of 50 percentage as per general category

Dear Julia ,

If you are join XYZ college and complete your 1st year course but if you will take admission in another college without informing XYZ college then it will trouble in future because you have already student of this college or university with particular registration number and it

Hey Jaywadmare, the anwer of your question is 34/3.

Also go through following explanation.

Explanation : a^2 = d ^12

b^3 = d ^12

c^9 = d ^12

after that logd ( d^12) 1/2 + 1/3 + 1/9 = logd (d^12)^ 51/54

= logd (d ^12 * 17/18)

= 1

In a triangle ABC cos(A+B)= cosAcosB-sinAsinB. cos(A-B)= cosAcosB+sinAsinB.

there by, by adding these two and multiplying the result by 2 times you get the desired answer. 4cosAcosB = 2[cos(A+B) + cos (A-B)]. This can also be done by interchanging the signs and the answer will remain the same.

Hey!

NO, I really dont think modern ABC is the appropriate book for NEET prep… Though it can help you with the 12 grade exams.

For NEET-UG,

1st, For the KNOWLEDGE part -primarily you should go for NCERT first surely and after that for extra knowledge Allen packages or Trueman’s