Question : A conical tent of height 10 m and base diameter 48 m was erected by a company in a park. Find the curved surface area of the tent (in m2).
Option 1: $576 \pi$
Option 2: $1248 \pi$
Option 3: $1152 \pi$
Option 4: $624 \pi$
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Correct Answer: $624 \pi$
Solution : A conical tent of height 10 m and base diameter 48 m was erected by a company in a park. Here base radius ($r$) = $\frac{48}{2}=24$ m and height ($h$) = 10 m Let the slant height = $l$ m Now, $l^2=h^2+r^2$ ⇒ $l^2=10^2+24^2$ ⇒ $l=676$ ⇒ $l=26$ m $\therefore$ The curved surface area of a tent = $\pi×r×l=\pi×24×26= 624\pi$ Hence, the correct answer is $624\pi$.
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Question : The lateral surface area of a frustum of a right circular cone, if the area of its base is 16$\pi$ cm2, the diameter of the circular upper surface is 4 cm and the slant height is 6 cm, will be:
Option 1: $30\pi$ cm2
Option 2: $48\pi$ cm2
Option 3: $36\pi$ cm2
Option 4: $60\pi$ cm2
Question : The volume of a solid right circular cylinder of height 8 cm is $392 \pi$ cm3. Its curved surface area (in cm2) is:
Option 1: $161 \pi$
Option 2: $96 \pi$
Option 3: $210 \pi$
Option 4: $112 \pi$
Question : The volume of a cylinder is 4312 cm3. Its curved surface area is one-third of its total surface area. Its curved surface area (in cm2) is: (Take $\pi=\frac{22}{7}$ )
Option 1: 572 cm2
Option 2: 528 cm2
Option 3: 660 cm2
Option 4: 616 cm2
Question : The volume of a conical tent is 1232 m3 and the area of its base is 154 sq m. Find the length of the canvas required to build the tent, if the canvas is 2 m in width. (Take $\pi=\frac{22}{7}$)
Option 1: 270 m
Option 2: 272 m
Option 3: 276 m
Option 4: 275 m
Question : The slant height of a cone is 20 cm. If the area of its base is 616 cm2, then what is the curved surface area of this cone? (use $\pi=\frac{22}{7}$)
Option 1: 960 cm2
Option 2: 400 cm2
Option 3: 1760 cm2
Option 4: 880 cm2
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