1462 Views

A force of 100N applied on a block of mass 3kg as shown in fig. The coefficient of friction between the surface and block is 1/4. The friction force acting on the block is


prachiverma2502 23rd May, 2020
Answer (1)
Mounika Sonti 25th May, 2020

Hello!!!

Hope you are doing great!!!

Given,

Force F=100N

mass=3kg

Coefficient of friction=μ  = 1/4

As we know,F=ma

a=F/m

a=100/3 m/s^2

acceleration=100/3 m/s^2

frictional force f=μ ma

therefore f=1/4*3*100/3

f=25N

Frictional force f=25N

Hope it helps!!!!!!

Related Questions

Amity University-Noida Journa...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Karnavati University BAJMC Ad...
Apply
100% Placements Assistance | 1200+ Recruiters
Navrachana University BJMC Ad...
Apply
Ranked as the 3rd Best Private University in Gujarat by Education World
UPES Dehradun -Media and Mass...
Apply
Last Date to Apply: 29th April | Ranked #45 Among Universities in India by NIRF | 1950+ Students Placed, 91% Placement, 800+ Recruiters
Shoolini University Admission...
Apply
NAAC A+ Grade | Ranked 503 Globally (QS World University Rankings 2026)
Amity-Noida M.A. (Journalism ...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books