1462 Views

A force of 100N applied on a block of mass 3kg as shown in fig. The coefficient of friction between the surface and block is 1/4. The friction force acting on the block is


prachiverma2502 23rd May, 2020
Answer (1)
Mounika Sonti 25th May, 2020

Hello!!!

Hope you are doing great!!!

Given,

Force F=100N

mass=3kg

Coefficient of friction=μ  = 1/4

As we know,F=ma

a=F/m

a=100/3 m/s^2

acceleration=100/3 m/s^2

frictional force f=μ ma

therefore f=1/4*3*100/3

f=25N

Frictional force f=25N

Hope it helps!!!!!!

Related Questions

Amity University | Journalism...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Amity School of Film & Drama ...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
UPES Dehradun -Media and Mass...
Apply
Ranked #45 Among Universities in India by NIRF | 1950+ Students Placed, 91% Placement, 800+ Recruiters
Pearl Academy Media Programs ...
Apply
100% Placement | 500+ Recruiters | Placement support for alumni for 5 Years
Amity, Noida M.A. (Journalism...
Apply
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Manav Rachna -MRIIRS-Journali...
Apply
Recognized as Category-1 Deemed to be University by UGC | 41,000 + Alumni Imprints Globally | Students from over 20+ countries
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books