Hi Varun,

Let's assume the two resistance coils be R1and R2

We have the three possible combinations

• R1 or R2 if they are used individually

Let, R2 be the larger of the two.

• R1*R2/R1+R2 if used in parallel

This is the smallest value. Parallel Resistance <R1 & <R2

• (R1+R2) if used in series.

This is the largest value. So, Series resistance >R1 & >R2

Hence, it given that  (R1+R2) = 8Ω

R1*R2/R1+R2 = 1.5Ω

So, on solving the above equations R1 and R2 comes to be 2Ω and 6Ω respectively.

Feel free to ask doubts in the Comment Section.

I hope this information helps you.

Good Luck!