Question : A vertical pillar 42 cm long casts a 35 cm long shadow. At the same time, a tower casts a shadow 25 m long. Find the height of the tower.
Option 1: 28 m
Option 2: 35 m
Option 3: 32 m
Option 4: 30 m
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Correct Answer: 30 m
Solution :
Length of the vertical pole, AB = 42 cm = 0.42 m
Length of the shadow of the pole, BC = 35 cm = 0.35 m
Let the height of the tower be $h$ m.
Length of the shadow of the tower, EF = 25 m (Given)
In $\triangle$ABC and $\triangle$DEF,
$\angle$C =$\angle$E (Angular elevation)
$\angle$B = $\angle$F = 90°
$∴$ $\triangle$ABC $\sim$ $\triangle$DFE (By Angle-Angle-Angle similarity criterion)
$∴ \frac{AB}{DF} = \frac{BC}{EF}$ (If two triangles are similar then their corresponding sides are proportional)
$∴ \frac{0.42}{h} = \frac{0.35}{25}$
⇒ $h = 30$ m
So, the height of the tower is 30 m.
Hence, the correct answer is 30 m.
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