Hello,

The reaction between chlorine and sulfur dioxide in water to remove excess chlorine is a redox reaction. Sulfur dioxide (SO2) acts as a reducing agent, reducing chlorine (Cl2) to chloride ions (Cl-), while itself being oxidized to sulfuric acid (H2SO4). The balanced equation for this reaction is:

Cl2(aq) + SO2(aq) + 2H2O(l) -> 2Cl-(aq) + H2SO4(aq)

Key points:

• Chlorine is reduced to chloride ions.
• Sulfur dioxide is oxidized to sulfuric acid.
• Occurs in aqueous solution.

Hope it helps !

Hello,

The reaction between chlorine and sulfur dioxide in water to remove excess chlorine is a redox reaction. Sulfur dioxide (SO2) acts as a reducing agent, reducing chlorine (Cl2) to chloride ions (Cl-), while itself being oxidized to sulfuric acid (H2SO4). The balanced equation for this reaction is:

Cl2(aq) + SO2(aq) + 2H2O(l) -> 2Cl-(aq) + H2SO4(aq)

Key points:

• Chlorine is reduced to chloride ions.
• Sulfur dioxide is oxidized to sulfuric acid.
• Occurs in aqueous solution.

Hope it helps !

Hello student,

The explanation for redox reaction for the removal of excess chlorine from water using sulfur dioxide (SO2) is as follows:

Explanation:

• Chlorine (Cl2) acts as the oxidizing agent and gets reduced to hydrochloric acid (HCl) .
  
  
• Sulfur dioxide (SO2) acts as the reducing agent and gets oxidized to sulfuric acid (H2SO4) .

In this reaction:

• Chlorine (Cl2) reduces from an oxidation state of +1 (in Cl2) to -1 (in HCl).
• Sulfur (S) in SO2 is oxidized from +4 to +6 (in H2SO4).

This reaction helps in removing excess chlorine and purifying the water.

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