Question : Directions: Four pairs of numbers have been given, out of which three are alike in some manner, while one is different. Choose out the odd one.
Option 1: 51 – 25
Option 2: 50 – 7
Option 3: 16 – 3
Option 4: 64 – 32
Correct Answer: 64 – 32
Solution :
Let's check each option –
First option:
51 – 25
51 + 25 = 76; 19 × 4 = 76; The sum of the pair is the multiple of 19.
Second option:
50 – 7
50 + 7 = 57; 19 × 3 = 57; The sum of the pair is the multiple of 19.
Third option:
16 – 3
16 + 3 = 19; 19 × 1 = 19; The sum of the pair is the multiple of 19.
Fourth option:
64 – 32
64 + 32 = 96; The sum of the pair is not the multiple of 19.
So, the fourth option is different from the others. Hence, the fourth option is correct.
