Question : If A's wealth is $\frac{4}{9}$ times of B's and C's is $\frac{7}{6}$ times of B's. What is the ratio of C's wealth to A's?
Option 1: 8:21
Option 2: 21:8
Option 3: 27:14
Option 4: 14:27
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Correct Answer: 21:8
Solution : Given: A's wealth is $\frac{4}{9}$ times of B. C's wealth is $\frac{7}{6}$ times of B. ⇒ A's wealth = B's wealth × $\frac{4}{9}$ ⇒ C's wealth = B's wealth × $\frac{7}{6}$ Ratio of C's wealth to A's wealth = $\frac{\frac{7}{6}}{\frac{4}{9}}$ $⇒\frac{21}{8}$ ⇒ 21:8 Therefore, option 2 is correct.
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Question : If $a: b: c=\frac{1}{4}: \frac{1}{3}: \frac{1}{2}$, then $\frac{a}{b}: \frac{b}{c}: \frac{c}{a}=$?
Option 1: 12 : 9 : 8
Option 2: 9 : 8 : 24
Option 3: 8 : 9 : 24
Option 4: 9 : 12 : 8
Question : What is the value of S $=\frac{1}{1×3×5}+\frac{1}{1×4}+\frac{1}{3×5×7}+\frac{1}{4×7}+\frac{1}{5×7×9}+\frac{1}{7×10}+....$ Up to 20 terms, then what is the value of S?
Option 1: $\frac{6179}{15275}$
Option 2: $\frac{6070}{14973}$
Option 3: $\frac{7191}{15174}$
Option 4: $\frac{5183}{16423}$
Question : If $\frac{(a+b)}{c}=\frac{6}{5}$ and $\frac{(b+c)}{a}=\frac{9}{2}$, then what is the value of $\frac{(a+c)}{b}\; ?$
Option 1: $\frac{9}{5}$
Option 2: $\frac{11}{7}$
Option 3: $\frac{7}{11}$
Option 4: $\frac{7}{4}$
Question : Directions: By interchanging the given two signs and numbers which of the following equations will be correct? × and +, 9 and 6
Option 1: 7 × 6 ÷ 3 + 9 – 8 = 17
Option 2: 6 × 8 – 9 ÷ 3 + 5 = 50
Option 3: 7 + 6 × 4 ÷ 9 – 8 = 8
Option 4: 9 × 7 + 4 ÷ 1 – 6 = 7
Question : The value of $15 \div 8-\frac{5}{4}$ of $\left(\frac{8}{3} \times \frac{9}{16}\right)+\left(\frac{9}{8} \times \frac{3}{4}\right)-\left(\frac{5}{32} \div \frac{5}{7}\right)+\frac{3}{8}$ is:
Option 1: 0
Option 2: 1
Option 3: 2
Option 4: 3
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