½value of [ (n/2)th + (n/2 +1) th] observations.

Median = ½[(6/2)th + (6/2 + 1) th] observations

Median = ½ [3th + 4th] observations

16 = ½ [(x - 2) + x

16 × 2 = 2x - 2

32 = 2x - 2

2x = 32 + 2

2x = 34

x = 34/2 = 17

x = 17

Hence, the value of x is 17.

Median of the data depends on the number of observations (n) .

i) If n is odd then median= value of [(n+1)/2]th observation

ii) If n is even then median= ½value of [ (n/2)th + (n/2 +1) th] observations.