Question : If $\sin \mathrm{C}=\frac{9}{10}$, then what is the value of $\cos ^2 \mathrm{C}$?
Option 1: $\frac{19}{100}$
Option 2: $\frac{81}{\sqrt{19}}$
Option 3: $\frac{19}{10}$
Option 4: $\frac{\sqrt{19}}{100}$
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Correct Answer: $\frac{19}{100}$
Solution : We know, $\sin^2 \mathrm{C} + \cos^2 \mathrm{C} = 1$ $⇒\cos^2 \mathrm{C} = 1 - \sin^2 \mathrm{C}$ Substituting $\sin \mathrm{C} = \frac{9}{10}$, $⇒\cos^2 \mathrm{C} = 1 - \left(\frac{9}{10}\right)^2 = 1 - \frac{81}{100} = \frac{19}{100}$ Hence, the correct answer is $ \frac{19}{100}$.
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Question : If $\sin A-\cos A=\frac{\sqrt{3}-1}{2}$, then the value of $\sin A\cdot \cos A$ is:
Option 1: $\frac{\sqrt{3}}{2}$
Option 2: $\frac{3}{2}$
Option 3: $\frac{\sqrt{3}}{4}$
Option 4: $\frac{1}{\sqrt{3}}$
Question : If $\theta$ is an acute angle and $\sin \theta \cos \theta=2 \cos ^3 \theta-\frac{1}{4} \cos \theta$, then the value of $\sin \theta$ is:
Option 1: $\frac{\sqrt{15}-1}{8}$
Option 2: $\frac{\sqrt{15}-1}{4}$
Option 3: $\frac{\sqrt{15}+1}{4}$
Option 4: $\frac{\sqrt{15}-1}{2}$
Question : If $\theta$ is an acute angle and $\sin \theta=\frac{13}{19}$, what is the value of $\cos \theta?$
Option 1: $\frac{6}{19}$
Option 2: $\frac{10 \sqrt{2}}{19}$
Option 3: $\frac{14}{19}$
Option 4: $\frac{8 \sqrt{3}}{19}$
Question : What is the value of the expression: $\sin A(1+\frac{\sin A}{\cos A})+\cos A(1+\frac{\cos A}{\sin A})$?
Option 1: $\sec A+\operatorname{cosec}A$
Option 2: $\sin \mathrm{A}+\cos \mathrm{A}$
Option 3: $\sin \mathrm{A}-\cos \mathrm{A}$
Option 4: $\sec \mathrm{A}-\operatorname{cosec} \mathrm{A}$
Question : If $\sin \theta \cos \theta=\frac{1}{\sqrt{3}}$ then the value of $\left(\sin ^4 \theta+\cos ^4 \theta\right)$ is:
Option 1: $1$
Option 2: $\frac{5}{3}$
Option 3: $\frac{2}{3}$
Option 4: $\frac{1}{3}$
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