Question : In a triangle the length of the opposite side of the angle which measures 45° is 8 cm, what is the length of the side opposite to the angle which measures 90°?
Option 1: $8\sqrt{2}$ cm
Option 2: $4\sqrt{2}$ cm
Option 3: $8\sqrt{3}$ cm
Option 4: $4\sqrt{3}$ cm
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Correct Answer: $8\sqrt{2}$ cm
Solution : Given: The length of the opposite side of the angle which measures 45° is 8 cm. In $\triangle ABC$, $\sin 45°=\frac{8}{AC}$ ⇒ $\frac{1}{\sqrt2}=\frac{8}{AC}$ ⇒ $AC=8\sqrt{2}$ Hence, the correct answer is $8\sqrt{2}$ cm.
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Question : In $\triangle$ABC, $\angle$A = $\angle$B = 60°, AC = $\sqrt{13}$ cm, the lines AD and BD intersect at D with $\angle$D = 90°. If DB = 2 cm, then the length of AD is:
Option 1: 3 cm
Option 2: 3.5 cm
Option 3: 4 cm
Option 4: 4.7 cm
Question : If $\tan(A+B)=\sqrt{3}$, and $\tan(A-B)=\frac{1}{\sqrt{3}}$, $\angle A+\angle B<90°$; $A\geq B$ then $\angle A$ is:
Option 1: 90°
Option 2: 30°
Option 3: 45°
Option 4: 60°
Question : Two similar triangles are given i.e. $\triangle$LMN ~ $\triangle$PQR, with measurement of angle and side as $\angle$ L = 40°, $\angle$ N = 80°, LM = 6 cm, LN = 8 cm and PQ = 7.5 cm. Find the value of $\angle$ Q and side PR, respectively.
Option 1: 60° and 20 cm
Option 2: 50° and 6.5 cm
Option 3: 40° and 10 cm
Option 4: 60° and 10 cm
Question : If the length of the side of an equilateral triangle is 8 cm, what is its area (in cm2)?
Option 1: $32\sqrt{3}$
Option 2: $16$
Option 3: $16\sqrt{3}$
Option 4: $32$
Question : In an equilateral triangle STU, inradius is $5 \sqrt{3 }\mathrm{~cm}$. What is the length of the side of this equilateral triangle?
Option 1: $20 \sqrt{3} \mathrm{~cm}$
Option 2: $18 \sqrt{3} \mathrm{~cm}$
Option 3: $30 \mathrm{~cm}$
Option 4: $24 \mathrm{~cm}$
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