Question : Solve {1 + 7 + (16 ÷ 8 ÷ 2)} + {(6 × 2² + 6)×$\frac{2}{\sqrt{36}}$}.
Option 1: 17
Option 2: 21
Option 3: 19
Option 4: 12
Correct Answer: 19
Solution : {1 + 7 + (16 ÷ 8 ÷ 2)} + {(6 × 2² + 6) × $\frac{2}{\sqrt{36}}$} = {8 + (1)} + {(6 × 4 + 6) × $\frac{1}{3}$} = 9 + 10 = 19 Hence, the correct answer is 19.
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Question : $\frac{1}{3-\sqrt{8}}-\frac{1}{\sqrt{8}-\sqrt{7}}+\frac{1}{\sqrt{7}-\sqrt{6}}-\frac{1}{\sqrt{6}-\sqrt{5}}+\frac{1}{\sqrt{5}-2}=?$
Option 1: 5
Option 2: 4
Option 3: 3
Option 4: 2
Question : Solve the following. $\frac{24 \div \frac{3}{8} \text { of }(8+2 \times \overline{7-3})+\left[\frac{2}{11} \div \frac{4}{55}-\left\{\frac{5}{8}+\frac{6}{16}\right\}\right]}{32 \div \overline{15-7}+75 \div(6+15 \div 3+4)} $
Option 1: $\frac{23}{27}$
Option 2: $\frac{9}{2}$
Option 3: $\frac{11}{18}$
Option 4: $\frac{15}{19}$
Question : The value of $8-3 \div 6$ of $2+\left(4 \div 4\right.$ of $\left.\frac{1}{4}\right) \div 8+\left(4 \times 8 \div \frac{1}{4}\right) \times \frac{1}{8}$ is:
Option 1: $\frac{7}{4}$
Option 2: $-\frac{97}{4}$
Option 3: $-\frac{7}{4}$
Option 4: $\frac{97}{4}$
Question : The value of $1-3 \div 6$ of $2+\left(4 \div 4\right.$ of $\left.\frac{1}{4}\right) \div 8+\left(4 \times 8 \div \frac{1}{4}\right) \times \frac{1}{8}$ is:
Option 1: $\frac{69}{4}$
Option 2: $-\frac{69}{4}$
Option 3: $\frac{7}{4}$
Option 4: $-\frac{7}{4}$
Question : If $\sin A=\frac{2}{3}$, then find the value of (7 – tan A)(3 + cos A).
Option 1: $\frac{61}{3}+\frac{17}{3 \sqrt{5}}$
Option 2: $\frac{61}{3 \sqrt{5}}+\frac{17}{3}$
Option 3: $\frac{61}{3}+\frac{17}{\sqrt{5}}$
Option 4: $\frac{61}{3}-\frac{17}{3 \sqrt{5}}$
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