Question : The base of a triangle is $12\sqrt{3}$ cm and two angles at the base are 30° and 60°, respectively. The altitude of the triangle is:
Option 1: $12$ cm
Option 2: $6$ cm
Option 3: $10\sqrt{3}$ cm
Option 4: $9$ cm
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Correct Answer: $9$ cm
Solution : Let BD be $x$ cm. $\therefore$ CD =$ (12\sqrt{3} - x) $cm. $\angle$ADB = $\angle$ADC = 90° From $\triangle$ ABD, $\tan 30°=\frac{AD}{BD}$ $⇒\frac{1}{\sqrt{3}}=\frac{AD}{x}$ So, AD = $\frac{x}{\sqrt{3}}$-----------(1) From $\triangle$ACD, $\tan 60°=\frac{AD}{CD}$ $⇒\sqrt{3}=\frac{AD}{ (12\sqrt{3} - x)}$ So, AD = $\sqrt{3}(12\sqrt{3}-x)$----------(2) From 1 and 2, we get, $\frac{x}{\sqrt{3}} = \sqrt{3}(12\sqrt{3}-x)$ $⇒x =36\sqrt{3}-3x$ $⇒4x = 36\sqrt{3}$ $⇒x = 9\sqrt{3}$ $\therefore$ AD $=\frac{x}{\sqrt{3}} = \frac{9\sqrt{3}}{\sqrt{3}} = 9$ cm Hence, the correct answer is $9$ cm.
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Question : In a triangle ABC, AB = 6$\sqrt{3}$ cm, AC = 12 cm and BC = 6 cm. Then the measure of $\angle B$ is equal to:
Option 1: 90°
Option 2: 45°
Option 3: 70°
Option 4: 60°
Question : The side of an equilateral triangle is 36 cm. What is the radius of the circle circumscribing this equilateral triangle?
Option 1: $13 \sqrt{3} \mathrm{~cm}$
Option 2: $10 \sqrt{3} \mathrm{~cm}$
Option 3: $12 \sqrt{3} \mathrm{~cm}$
Option 4: $9 \sqrt{3} \mathrm{~cm}$
Question : On the ground, there is a vertical tower with a flagpole on its top. At a point 9 metres away from the foot of the tower, the angles of elevation of the top and bottom of the flagpole are 60° and 30°, respectively. The height of the flagpole is:
Option 1: $5\sqrt{3}$ metres
Option 2: $6\sqrt{3}$ metres
Option 3: $6\sqrt{2}$ metres
Option 4: $6\sqrt{5}$ metres
Question : If the sum and difference of two angles are 135° and $\frac{\pi}{12}$, respectively, then the value of the angles in degree measure is:
Option 1: 70° and 65°
Option 2: 75° and 60°
Option 3: 45° and 90°
Option 4: 80° and 55°
Question : The side of an equilateral triangle is 12 cm. What is the radius of the circle circumscribing this equilateral triangle?
Option 1: $6 \sqrt{3}\ \text{cm}$
Option 2: $4\sqrt{3}\ \text{cm}$
Option 3: $9 \sqrt{3}\ \text{cm}$
Option 4: $5\sqrt{3}\ \text{cm}$
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