the sum of two forceacting at a point is 16N if the resultant force is 8N and its direction is perpendivular to the smaller force then the force are
Answer (1)
Student Expert
8th Oct, 2019
Let us assume the force of smaller magnitude be A and the force of larger magnitude be B.
here,it is clearly given that the resultant force is R perpendicular to small force. hence, we can say that b is the hyopetenuse .
therefore, b² = R² + A²
=> R² = b² - A²
= 8²
= 64 ...........(.1)
here, it is also given that
A + B = 16
therefore , B = 16 - A ..........................( 2 ).
Now, by substituting ( 2 ) in ( 1 ).we get,
( 16 - A ) ²- A² = 64
=> 256 - 32A + A² - A² = 64
32A = 256 - 64 = 192
A = 192 / 32
= 6
hence, we get the result
B = 16 - A = 16 - 6 = 10
therefore, the magnitude of the two vectors are 6 and 10.
thankyou
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