Question : What is the ratio of the mean proportional between 1.6 and 3.6 and the third proportional of 5 and 8?
Option 1: 2 : 15
Option 2: 5 : 16
Option 3: 3 : 16
Option 4: 4 : 15
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Correct Answer: 3 : 16
Solution : Mean proportion of 1.6 and 3.6 $=\sqrt{ab}=\sqrt{1.6\times 3.6}=2.4$ Now, the third proportion of 5 and 8 $=\frac{b^2}{a}=\frac{8^2}{5}=\frac{64}{5}$ $\therefore$ Ratio of mean proportion to third proportion = $2.4:\frac{64}{5}$ = 12 : 64 = 3 : 16 Hence, the correct answer is 3 : 16.
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Question : Given that the ratio of the altitude of two triangles is 4 : 5, the ratio of their areas is 3 : 2, the ratio of their corresponding bases is:
Option 1: 8 : 15
Option 2: 15 : 8
Option 3: 5 : 8
Option 4: 8 : 5
Question : The third proportional of $a$ and $\frac{b^4}{4a}$ is:
Option 1: $\frac{b^8}{16 a^2}$
Option 2: $\frac{b^8}{8 a^2}$
Option 3: $\frac{b^8}{8 a^3}$
Option 4: $\frac{b^8}{16 a^3}$
Question : A, B, and C invested capital in the ratio of 3 : 4 : 8. At the end of the business term, they received the profit in the ratio of 2 : 3 : 5. What is the ratio of their invested time?
Option 1: 15 : 16 : 13
Option 2: 13 : 18 : 15
Option 3: 16 : 18 : 15
Option 4: 16 : 21 : 18
Question : The mean proportional of 6 and 54 is _______ more than 15.
Option 1: 3
Option 2: 6
Option 3: 4
Option 4: 5
Question : The value of $15 \div 8-\frac{5}{4}$ of $\left(\frac{8}{3} \times \frac{9}{16}\right)+\left(\frac{9}{8} \times \frac{3}{4}\right)-\left(\frac{5}{32} \div \frac{5}{7}\right)+\frac{3}{8}$ is:
Option 1: 0
Option 2: 1
Option 3: 2
Option 4: 3
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