Bodmas Rule in Simplification

BODMAS Rule in Simplification: Definition, Formula, Questions, Examples & Tricks

The BODMAS Rule is one of the most important concepts in mathematics and quantitative aptitude. It helps students solve mathematical expressions in the correct order and avoids mistakes in simplification questions. Whether you are preparing for school exams or competitive exams like SSC, Banking, NDA, CAT, or Railways, understanding the BODMAS Rule is essential for fast and accurate problem-solving.

What is the BODMAS Rule in Mathematics?

BODMAS is a standard mathematical rule used to decide the correct sequence of operations while solving an expression that contains multiple operators like addition, subtraction, multiplication, division, powers, and brackets.

Without BODMAS, the same expression can give different answers depending on how it is solved. This rule ensures that everyone gets the same correct answer.

Definition of BODMAS Rule with Example

The BODMAS Rule states that mathematical operations must be solved in a fixed order:

• First Brackets
• Then Orders (powers, roots, exponents)
• Then Division
• Then Multiplication
• Then Addition
• Finally Subtraction

Example

Solve:

$8 + 2 \times (6 - 3)$

Step 1: Solve bracket first

$(6 - 3) = 3$

Now expression becomes:

$8 + 2 \times 3$

Step 2: Perform multiplication

$2 \times 3 = 6$

Now expression becomes:

$8 + 6$

Step 3: Perform addition

$8 + 6 = 14$

Final Answer = 14

This is a basic example of simplification using the BODMAS Rule.

Full Form of BODMAS Explained

BODMAS stands for:

This order must always be followed while solving arithmetic expressions.

Many students confuse multiplication and division or addition and subtraction, but both should be solved from left to right when they appear together.

Why BODMAS Rule is Important in Simplification

The BODMAS Rule is important because it removes confusion in calculations and ensures accuracy.

It helps in:

• solving arithmetic simplification questions
• algebraic expressions
• fractions and decimals
• percentage and ratio problems
• aptitude test calculations
• competitive exam speed solving

Most simplification questions in exams are directly based on BODMAS.

Learning BODMAS improves both speed and accuracy.

Real-Life Applications of BODMAS Rule

BODMAS is not limited to textbooks—it is used in daily life calculations too.

Shopping Bill Calculations

Suppose you buy 3 items worth ₹200 each and then get a ₹100 discount.

Correct calculation:

$(3 \times 200) - 100 = 500$

Wrong order can give a completely incorrect answer.

Banking and Finance Calculations

Interest calculations, EMI calculations, and discount percentages follow BODMAS.

Time and Work Calculations

In aptitude problems involving rates and time, correct order of operations is necessary.

Percentage and Profit-Loss Questions

Competitive exam questions on percentages and profit-loss depend heavily on proper simplification.

This makes BODMAS a practical and scoring topic.

Order of Operations in BODMAS Rule

To solve simplification questions correctly, students must understand the exact order of operations used in the BODMAS Rule.

Brackets (B)

Brackets are solved first because they contain the most immediate operations.

Types of brackets include:

• $( )$ small brackets
• ${ }$ curly brackets
• $[ ]$ square brackets
• vinculum (line bar)

Example

$12 - (4 + 2)$

First solve:

$(4 + 2) = 6$

Then:

$12 - 6 = 6$

Orders or Of (O)

Orders include:

• powers
• roots
• exponents
• square roots
• cube roots

Example

$3 + 2^3$

First solve power:

$2^3 = 8$

Then:

$3 + 8 = 11$

Division (D)

Division is solved before multiplication if it appears first from left to right.

Example

$20 \div 5 \times 2$

First division:

$20 \div 5 = 4$

Then multiplication:

$4 \times 2 = 8$

Multiplication (M)

Multiplication is performed after division or from left to right if both exist together.

Example

$4 \times 3 + 2$

First multiplication:

$4 \times 3 = 12$

Then addition:

$12 + 2 = 14$

Addition (A)

Addition is done after multiplication and division.

Example

$10 + 6 - 2$

Addition and subtraction are solved from left to right.

$10 + 6 = 16$

Subtraction (S)

Subtraction is the final step in most expressions.

Example

$16 - 2 = 14$

Understanding this full order is the key to solving simplification questions correctly.

Step-by-Step Method to Apply BODMAS Rule

Following a proper step-by-step method helps avoid mistakes and improves exam performance.

Solve Brackets First

Always begin with the innermost bracket.

Example

$15 - (3 + 2)$

First: $(3 + 2) = 5$

Then: $15 - 5 = 10$

Simplify Powers, Roots, and Orders

After brackets, solve powers and roots.

Example

$5 + \sqrt{16}$

$\sqrt{16} = 4$

So: $5 + 4 = 9$

Perform Division and Multiplication

Solve division and multiplication from left to right.

Example

$24 \div 6 \times 3$

$24 \div 6 = 4$

$4 \times 3 = 12$

Complete Addition and Subtraction

Finally solve addition and subtraction from left to right.

Example

$12 + 8 - 5$

$12 + 8 = 20$

$20 - 5 = 15$

Verify the Final Answer

Always recheck:

• bracket simplification
• operator priority
• sign errors
• multiplication and division mistakes

This step improves accuracy and reduces silly mistakes.

BODMAS Rule Formula and Shortcut Tricks

Learning shortcut methods makes simplification much faster in competitive exams.

Standard BODMAS Formula

The standard order is:

$\text{B} \rightarrow \text{O} \rightarrow \text{D} \rightarrow \text{M} \rightarrow \text{A} \rightarrow \text{S}$

This is the most important simplification rule.

Important Simplification Shortcuts Using BODMAS

Some useful tricks include:

• Solve from inside brackets outward
• Division and multiplication are equal priority
• Addition and subtraction are equal priority
• Always solve left to right for same-priority operators
• Negative signs must be handled carefully

These tricks save time in MCQ-based exams.

Common Calculation Mistakes to Avoid

Students often make these mistakes:

• solving multiplication before brackets
• ignoring powers and roots
• confusing division and multiplication priority
• sign mistakes with negative numbers
• wrong simplification of fractions

Avoiding these mistakes can significantly improve scores in aptitude exams.

Understanding the rule of BODMAS

1. Brackets (B):

In mathematics, if a symbol is used to group parts of an expression or equation, it is called Brackets.

It indicates that the operations within the brackets should be performed first according to the order of operations.

There are three main types of brackets.

• First brackets or parentheses, ()

• Second brackets or curly braces, {}

• Third brackets or square brackets, []

If an expression has all three brackets in it, then the order of operations should be
first brackets > second brackets > third brackets.

2. Of (O):

In mathematical expressions, the term "of" means multiplication. So, after completing the operations within brackets, the next step is multiplying the numbers wherever the term "of" appears.

3. Division (D):

The division is one of the four basic arithmetic operations. It is the process of determining how many times one number is contained within another. It will be done from left to right in the expression.

4. Multiplication (M):

Multiplication is one of the four basic arithmetic operations. It is the process of repeatedly adding the same number. It will be done from left to right in the expression.

5. Addition (A):

Addition is a fundamental operation of the four basic arithmetic operations. It is the process of getting a total sum by combining two or more numbers. It will be done from left to right in the expression.

6. Subtraction (S):

Subtraction is a fundamental operation of the four basic arithmetic operations. It is the process of finding the difference between two numbers by removing the value of one number from another. It will be done from left to right in the expression.

Understanding the rule of BIDMAS

The BIDMAS rule is used to simplify and get the value of an expression if it has brackets, indices, and arithmetic operations like addition, subtraction, multiplication, and division. It helps us to remember which operations to do first.

When faced with a mathematical expression involving multiple types of brackets, indices, and arithmetic operations, knowing which operation to perform first can be challenging. This confusion can lead to incorrect results and wasted time without a clear method.
The BIDMAS rule provides a straightforward approach to handle these expressions systematically.

First, the operations of brackets are done, and then the exponents or roots are evaluated. After that, we will divide and multiply from left to right in that order. Addition comes next and Subtraction at the end. Both these operations should be done from left to right.

Meaning and Order of Operators in BIDMAS

1. Brackets (B):

In mathematics, if a symbol is used to group parts of an expression or equation, it is called Brackets.

It indicates that the operations within the brackets should be performed first according to the order of operations.

There are three main types of brackets.

• First brackets or parentheses, ()

• Second brackets or curly braces, {}

• Third brackets or square bracket, []

If an expression has all three brackets in it, then the order of operations should be
first brackets > second brackets > third brackets.

2. Indices (I):

Indices or exponents represent the power or roots of numbers and need to be simplified to their standard form.

For example, 22 simplifies to 4, and 52 simplifies to 25.

3. Division (D):

The division is one of the four basic arithmetic operations. It is the process of determining how many times one number is contained within another. It will be done from left to right in the expression.

4. Multiplication (M):

Multiplication is one of the four basic arithmetic operations. It is the process of repeatedly adding the same number. It will be done from left to right in the expression.

5. Addition (A):

Addition is a fundamental operation of the four basic arithmetic operations. It is the process of getting a total sum by combining two or more numbers. It will be done from left to right in the expression.

6. Subtraction (S):

Subtraction is a fundamental operation of the four basic arithmetic operations. It is the process of finding the difference between two numbers by removing the value of one number from another. It will be done from left to right in the expression.

Understanding the rule of PEDMAS

The PEDMAS rule is used to simplify and get the value of an expression if it has parentheses, exponents, and arithmetic operations like addition, subtraction, multiplication, and division. It helps us to remember which operations to do first.

When faced with a mathematical expression involving multiple types of parentheses, exponents, and arithmetic operations, knowing which operation to perform first can be challenging. This confusion can lead to incorrect results and wasted time without a clear method.
The PEDMAS rule provides a straightforward approach to handle these expressions systematically.

First, do the operations of parentheses, and then evaluate the exponents or roots. After that, we will divide and multiply from left to right in that order. Addition comes next and Subtraction at the end. Both these operations should be done from left to right.

Meaning and Order of Operators in PEDMAS

1. Parentheses (P):

Parentheses generally mean the Brackets “()”. But in mathematical expressions, we also have to evaluate other grouping symbols like square brackets “[]” and curly braces “{}”.

2. Exponents (E):

Exponents represent the power or roots of numbers and need to be simplified to their standard form.

For example, 22 simplifies to 4, and 52 simplifies to 25.

3. Division (D):

The division is one of the four basic arithmetic operations. It is the process of determining how many times one number is contained within another. It will be done from left to right in the expression.

4. Multiplication (M):

Multiplication is one of the four basic arithmetic operations. It is the process of repeatedly adding the same number. It will be done from left to right in the expression.

5. Addition (A):

Addition is a fundamental operation of the four basic arithmetic operations. It is the process of getting a total sum by combining two or more numbers. It will be done from left to right in the expression.

6. Subtraction (S):

Subtraction is a fundamental operation of the four basic arithmetic operations. It is the process of finding the difference between two numbers by removing the value of one number from another. It will be done from left to right in the expression.

Difference Between BODMAS and PEMDAS

Many students get confused between BODMAS and PEMDAS because both are used to solve mathematical expressions in the correct order. The good news is that both rules follow the same basic principle—the correct sequence of operations in simplification. The only difference lies in the terminology used in different countries.

Understanding the difference between BODMAS and PEMDAS is important for school mathematics, quantitative aptitude, and competitive exam preparation.

BODMAS vs PEMDAS Explained

BODMAS and PEMDAS are both rules of order of operations used to solve arithmetic and algebraic expressions correctly.

BODMAS stands for:

• Brackets
• Orders
• Division
• Multiplication
• Addition
• Subtraction

PEMDAS stands for:

• Parentheses
• Exponents
• Multiplication
• Division
• Addition
• Subtraction

Although the names are slightly different, both rules are based on the same logic.

In BODMAS, the word “Brackets” is used, while PEMDAS uses “Parentheses.”

Similarly, BODMAS uses “Orders” for powers and roots, while PEMDAS uses “Exponents.”

The mathematical process remains the same.

Example

Solve:

$12 - 2 \times (3 + 1)$

Using BODMAS:

Step 1: Bracket first

$(3 + 1) = 4$

Step 2: Multiplication

$2 \times 4 = 8$

Step 3: Subtraction

$12 - 8 = 4$

Using PEMDAS, the answer will also be exactly the same.

This proves that both systems give the same final result.

Which Rule is Used in India?

In India, the BODMAS Rule is the standard method taught in schools and used in competitive exams.

Most textbooks, school exams, CBSE, ICSE, and government exam preparation materials follow BODMAS.

Exams like:

• SSC
• Banking Exams
• NDA
• Railways
• CAT
• UPSC foundation mathematics

mainly use the BODMAS Rule for simplification questions.

PEMDAS is more commonly used in countries like the United States.

Students preparing for Indian exams should focus mainly on BODMAS.

Similarities and Differences in Order of Operations

Both BODMAS and PEMDAS help in solving expressions correctly by following operator priority.

Similarities

The main similarities are:

• both solve brackets first
• both solve powers or exponents next
• both give priority to multiplication and division before addition and subtraction
• both solve operators of the same priority from left to right
• both produce the same final answer

This means there is no mathematical conflict between them.

Differences

The differences are mainly in naming conventions.

Many students wrongly think PEMDAS means multiplication must always be done before division. This is incorrect.

Multiplication and division have equal priority and must be solved from left to right.

The same rule applies to addition and subtraction.

Example

Solve:

$20 \div 5 \times 2$

Correct method:

$20 \div 5 = 4$

Then:

$4 \times 2 = 8$

Not:

$5 \times 2 = 10$ first

This is a very common mistake in competitive exams.

Understanding these similarities and differences helps students solve simplification questions more accurately and avoid confusion between BODMAS and PEMDAS.

Application of BODMAS in Simplification Problems

• Simplify the following expression using the BODMAS rule:
• {1 + 7 + (16 ÷ 8 ÷ 2)} + {(6 × 22 + 6) × $\frac{2}{6}$}
• Here, there are two types of brackets, first brackets and curly braces.
• First, operate on the terms that are inside the first brackets from left to right.
• i.e., (16 ÷ 8 ÷ 2) = 1 and (6 × 22 + 6) = 30
• Expression becomes: {1 + 7 + 1} + {30 × $\frac{2}{6}$}
• Now, operation on the terms of curly braces will be done.
• i.e., {1 + 7 + 1} = 9 and {30 × $\frac{2}{6}$} = 10
• Expression becomes: 9 + 10
• Finally, Addition can be done.
• 9 + 10 = 19
• Hence, the value of the expression is 19.

• What is the value of 2160 × 3 ÷ 144 + 13 - 2?

• In this expression, there are no brackets, only arithmetic operations are there.
• So, as per the BODMAS rule,
• First, we will do Division, then multiplication from left to right.
• i.e., $2160 × \frac{3}{144}=45$
• Expression becomes: 45 + 13 - 2
• Now, Addition and Subtraction will be done from left to right.
• 45 + 13 - 2 = 56
• Hence, the value of the expression is 56.

Practice Questions

Q1. Simplify the following using BODMAS rule:
(16 + 14) ÷ 2 – 12 + 16 × 4 – 28 + 13 (–16 + 13)

1. 6

2. 0

3. -3

4. 3

Answer:

Given: (16 + 14) ÷ 2 – 12 + 16 × 4 – 28 + 13 (–16 + 13)

Using the BODMAS rule, we get,

= 30 ÷ 2 – 12 + 16 × 4 – 28 + 13 (–3)

= 15 – 12 + 64 – 28 – 39

= 3 + 64 – 67

= 0

Hence, the correct answer is option(B).

Q2. What is the value of $\frac{3}{2} \div \frac{1}{7} \times[(\frac{1}{2} - \frac{1}{3}) \div \frac{1}{42}]?$

1. $72 \frac{1}{3}$

2. $73 \frac{1}{2}$

3. $72 \frac{1}{2}$

4. $71 \frac{2}{3}$

Answer:

Given: $\frac{3}{2} \div \frac{1}{7} \times[(\frac{1}{2} - \frac{1}{3}) \div \frac{1}{42}]$

Applying the BODMAS rule, we get,

$=\frac{3}{2} \div \frac{1}{7} \times[(\frac{3-2}{6}) \div \frac{1}{42}]$

$=\frac{3}{2} \div \frac{1}{7} \times[\frac{1}{6} \div \frac{1}{42}]$

$=\frac{3}{2} \div \frac{1}{7} \times[\frac{1}{6} \times{42}]$

$=\frac{3}{2} \div \frac{1}{7} \times7$

$=\frac{21}{2}\times 7$

$=\frac{147}{2}$

$=73\frac{1}{2}$

Hence, the correct answer is $73\frac{1}{2}$.

Q3. If $M =\left ( \frac{3}{7} \right ) ÷ \left ( \frac{6}{5} \right ) ×\left ( \frac{2}{3} \right ) + \left ( \frac{1}{5} \right ) ×\left ( \frac{3}{2} \right )$ and $N = \left ( \frac{2}{5} \right ) × \left ( \frac{5}{6} \right ) ÷ \left ( \frac{1}{3} \right ) + \left ( \frac{3}{5} \right ) × \left ( \frac{2}{3} \right ) ÷ \left ( \frac{3}{5} \right )$, then what is the value of $\frac{M}{N}$?

1. $\frac{207}{560}$

2. $\frac{339}{1120}$

3. $\frac{113}{350}$

4. $\frac{69}{175}$

Answer:

$M =\left (\frac{3}{7}\right) ÷ \left (\frac{6}{5} \right) ×\left (\frac{2}{3} \right) + \left (\frac{1}{5} \right) ×\left (\frac{3}{2}\right)$

$M =\left (\frac{3}{7} \right) × \left (\frac{5}{6} \right) ×\left (\frac{2}{3} \right) + \left (\frac{1}{5} \right) ×\left (\frac{3}{2} \right)$

$M = \frac{5}{21}+\frac{3}{10}$

$M = \frac{113}{210}$

$N = \left (\frac{2}{5} \right) × \left (\frac{5}{6} \right) ÷ \left (\frac{1}{3} \right) + \left (\frac{3}{5} \right) × \left (\frac{2}{3} \right) ÷ \left (\frac{3}{5} \right)$

$N = \left (\frac{2}{5} \right) × \left (\frac{5}{6} \right) ×3+ \left (\frac{3}{5} \right) × \left (\frac{2}{3} \right) × \left (\frac{5}{3} \right)$

$N =1 + \left (\frac{2}{3} \right)$

$N = \left (\frac{5}{3} \right)$

$\frac{M}{N} = \frac{113}{210}×\frac{3}{5} = \frac{113}{350}$

Hence, the correct answer is $\frac{113}{350}$.

Q4. Simplify the following using BODMAS rule:

$\{[(x-5)(x-1)]-[(9 x-5)(9x-1)]\} \div 16x$

1. $2x(5x-3)$

2. $-(5x-3)$

3. $x(5x-3)$

4. $-6x(5x-3)$

Answer:

Given: $\{[(x-5)(x-1)]-[(9 x-5)(9x-1)]\} \div 16x$

$= [(x^{2}-x-5x+5)-[(81x^{2}-9x-45x+5)]\div 16x$

$= [(x^{2}-6x+5)-[(81x^{2}-54x+5)]\div 16x$

$= [(x^{2}-6x+5-81x^{2}+54x-5)]\div 16x$

$= [-80x^{2}+48x]\div 16x$

$=[-5x+3]$

$=-(5x-3)$

Hence, the correct answer is $-(5x-3)$.

Q5. If $\left(2^2+4\right)^2 \times(3-5)+20 \%$ of $400+x \%$ of $30=30 \%$ of $30$, find the value of $x$.

1. 150

2. 120

3. 190

4. 160

Answer:

$\left(2^2+4\right)^2 \times(3-5)+20 \%$ of $400+x \%$ of $30=30 \%$ of $30$

⇒ $(4+4)^2 \times (-2) + \frac{20\times 400}{100} + \frac{30x}{100} = \frac{30\times 30}{100}$

⇒ $8^2 \times (-2) + 80 + 0.3x = 9$

⇒ $-128 + 80 + 0.3 x = 9$

⇒ $-48 + 0.3x = 9$

⇒ $0.3x = 57$

$\therefore x = \frac{570}{3} = 190$

Hence, the correct answer is 190.

Q6. Simplify the following expression.

$\frac{7}{10} \div \frac{3}{7}$ of $\left(2 \frac{3}{10}+2 \frac{3}{5}\right)+\frac{1}{5} \div 1 \frac{2}{5}-\frac{2}{7}$

1. $-\frac{4}{21}$

2. $\frac{5}{21}$

3. $\frac{4}{21}$

4. $-\frac{5}{21}$

Answer:

$\frac{7}{10} \div \frac{3}{7}$ of $\left(2 \frac{3}{10}+2 \frac{3}{5}\right)+\frac{1}{5} \div 1 \frac{2}{5}-\frac{2}{7}$

Converting mixed fractions to fractions,

= $\frac{7}{10} \div \frac{3}{7}$ of $\left(\frac{23}{10}+\frac{13}{5}\right)+\frac{1}{5} \div \frac{7}{5}-\frac{2}{7}$

Applying BODMAS, we get,

= $\frac{7}{10} \div \frac{3}{7}\ $ of $ (\frac{49}{10})+\frac{1}{5} \div \frac{7}{5}-\frac{2}{7}$

= $\frac{7}{10} \div (\frac{21}{10})+\frac{1}{7}-\frac{2}{7}$

= $\frac{1}{3}-\frac{1}{7}$

= $\frac{4}{21}$

Hence, the correct answer is $\frac{4}{21}$.

Q7. The value of

$51 \div\left\{25+(25\right.$ of $12 \div 30)-\left(5^4 \div 5\right.$ of 125$\left.)\right\}$ is:

1. $\frac{2}{3}$

2. $\frac{3}{2}$

3. $-\frac{2}{3}$

4. $-\frac{3}{2}$

Answer:

Given: $51\div\left\{25+(25\right.$ of $12 \div 30)-\left(5^4 \div 5\right.$ of 125$\left.)\right\}$

$= 51\div\left\{25+(300\right.$ $ \div 30)-\left(5^4 \div 5^4\right.$$\left.)\right\}$

$= 51÷[25+10-1]$

$= \frac{51}{34}$

$= \frac{3}{2}$

Hence, the correct answer is $\frac{3}{2}$.

Q8. The value of $3\frac{1}{2} - [2\frac{1}{4}+ 1\frac{1}{4} - \frac{1}{2}(1\frac{1}{2}-\frac{1}{3} -\frac{1}{6})]$ is:

1. $\frac{1}{2}$

2. $2\frac{1}{2}$

3. $3\frac{1}{2}$

4. $9\frac{1}{2}$

Answer:

Given: $3\frac{1}{2} - [2\frac{1}{4}+ 1\frac{1}{4} -\frac{1}{2}(1\frac{1}{2}-\frac{1}{3} -\frac{1}{6})]$

$=3\frac{1}{2} -[2\frac{1}{4}+ 1\frac{1}{4} - \frac{1}{2}(\frac{3}{2}-\frac{1}{2})]$

$=3\frac{1}{2} -[2\frac{1}{4}+ 1\frac{1}{4} - \frac{1}{2}\times 1]$

$=3\frac{1}{2} -[\frac{9}{4}+\frac{5}{4} - \frac{1}{2}]$

$=3\frac{1}{2} -[\frac{14}{4} - \frac{1}{2}]$

$=3\frac{1}{2} -[\frac{12}{4}]$

$=\frac{7}{2} -3$

$=\frac{1}{2}$

Hence, the correct answer is $\frac{1}{2}$.

Q9. Simplify: $\sqrt{\frac{4\frac{1}{7}-2\frac{1}{4}}{3\frac{1}{2}+1\frac{1}{7}}+\frac{2}{2+\frac{1}{2+\frac{1}{5-\frac{1}{5}}}}}$

1. 1

2. $\sqrt{\frac{265}{130}}$

3. 2

4. $\sqrt{\frac{159}{130}}$

Answer:

Given: $\sqrt{\frac{4\frac{1}{7}-2\frac{1}{4}}{3\frac{1}{2}+1\frac{1}{7}}+\frac{2}{2+\frac{1}{2+\frac{1}{5-\frac{1}{5}}}}}$

= $\sqrt{\frac{\frac{29}{7}-\frac{9}{4}}{\frac{7}{2}+\frac{8}{7}}+\frac{2}{2+\frac{1}{2+\frac{5}{24}}}}$

= $\sqrt{\frac{\frac{53}{28}}{\frac{65}{14}}+\frac{2}{2+\frac{24}{53}}}$

= $\sqrt{\frac{53}{130}+\frac{106}{130}}$

= $\sqrt{\frac{159}{130}}$

Hence, the correct answer is $\sqrt{\frac{159}{130}}$.

Q10. Simplify the following expression.

2 + (30 – 26)2 ÷ 8{3 – 2} × 0.5

1. 2

2. 1

3. 3

4. 0

Answer:

Given: 2 + (30 – 26)2 ÷ 8{3 – 2} × 0.5

= 2 + 42 ÷ 81 × 0.5

= 2 + 16 ÷ 8 × 0.5

= 2 + 2 × 0.5

= 2 + 1

= 3

Hence, the correct answer is Option (C), 3.

Related Quantitative Aptitude Topics

This section covers other important Quantitative Aptitude topics related to simplification and BODMAS Rule, helping students strengthen their overall problem-solving skills. It includes key concepts from arithmetic, algebra, percentages, ratios, and number systems that are frequently asked in competitive exams.